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scoray [572]
3 years ago
11

The athletic department at Hornell High School would like to determine the average height of the 1200 male students at the schoo

l.
Select from the following survey methods that would allow the department to draw valid conclusions about the average height of the male students at Hornell High School.
A
Measure the height of every male student at Hornell High School and take an arithmetic average to determine the height.
B
Measure the height of every student on the men's basketball team at Hornell High School and take the arithmetic average.
C
Measure the height of every student on the men's football and men's volleyball teams at Hornell High School and take the arithmetic average.
D
Assign unique student ids to all 1200 male students at Hornell High School. Use a computer program to randomly select 120 male students at Hornel High School, measure their heights and take the arithmetic average.
Mathematics
1 answer:
krok68 [10]3 years ago
3 0
D; It would be D because picking and choosing from different sports teams doesn’t make it data. Choosing random students would make it more diverse for the height
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Answer:

I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

\frac{dI}{dt}=a*I*(1000-I)

Rearranging and integrating

\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t

At the initial breakout (t=0) there was one trooper infected (I=1)

-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755

In two days (t=2) there were 5 troopers infected

-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725

Rearranging, we can model the number of infected troops (I) as

-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755}  \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}

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Based on the streams of income that Li Wei has, we can calculate that he has a total passive income of <u>$3,010.</u>

Passive income refers to income that is made without a person actively involving themselves in the activity generating the income.

In this scenario, the passive income sources are:

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Total passive income therefore is:

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In conclusion, the total passive income is $3,010.

<em>Find out more at brainly.com/question/1246309. </em>

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