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k0ka [10]
3 years ago
7

What is the solution to the system of equations represented by these two lines?

Mathematics
2 answers:
Umnica [9.8K]3 years ago
8 0
The solution to the two lines is the point at which they intersect. The point at which they intersect is (3,2).

The answer is C) (3,2).
zepelin [54]3 years ago
3 0
The solution is (3,2) cause both of the lines intersect at one point (which is a solution),and that point is (3,2) :)
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If each of the following represents the slope of a line (or line segment), give the slope a line that is perpendicular to it. (a
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Answer:

m_2 = -\frac{3}{4} -- (a)

m_2 = -\frac{7}{3} -- (b)

m_2 = -\frac{1}{4} --- (c)

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Step-by-step explanation:

Given

a.\ m = \frac{4}{3}

b.\ m = \frac{3}{7}

c.\ m = 4

d.\ m = \frac{1}{3}

Required

Determine the slope of a perpendicular line

In geometry, the condition for perpendicularity is:

m_2 = -\frac{1}{m}

This formula will be applied in solving these questions.

a.\ m = \frac{4}{3}

m_2 = -\frac{1}{m}

Substitute 4/3 for m

m_2 = -\frac{1}{4/3}

Express as a proper division

m_2 = -1/ \frac{4}{3}

Convert to *

m_2 = -1* \frac{3}{4}

m_2 = -\frac{3}{4}

b.\ m = \frac{3}{7}

m_2 = -\frac{1}{m}

Substitute 3/7 for m

m_2 = -\frac{1}{3/7}

Express as a proper division

m_2 = -1/ \frac{3}{7}

Convert to *

m_2 = -1* \frac{7}{3}

m_2 = -\frac{7}{3}

c.\ m = 4

m_2 = -\frac{1}{m}

Substitute 4 for m

m_2 = -\frac{1}{4}

d.\ m = \frac{1}{3}

m_2 = -\frac{1}{m}

Substitute 1/3 for m

m_2 = -\frac{1}{1/3}

Express as a proper division

m_2 = -1/ \frac{1}{3}

Convert to *

m_2 = -1* \frac{3}{1}

m_2 = -\frac{3}{1}

m_2 = -3

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Step-by-step explanation:

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