Question

What is the solution to the following system of linear equations?

Answer 1

There are two ways to solve system of equations.

1) substitution method

2) elimination method

4x - y = -6

x - 2y = -5

For thus problem, i'll be using the substitute method.

So, using the equation x - 2y = -5:

Solve for "x" by adding 2y to both sides of the equation.

x = 2y - 5

Now we know what "x" is, we can substitute it in the other equation.

4x - y = -6

4(2y - 5) - y = -6

8y - 20 - y = -6

7y - 20 = -6

7y = 14

y = 2

We now know the numerical value of y. So, all we have to do is plug in y into either system of equation to solve for the numerical value of x.

4x - 2 = -6 x - 2y = -5

4x = -4 x - 2(2) = -5

x = -1 x - 4 = -5

x = -1



The solution is (-1, 2) where x equals -1 and y equals 2.