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Furkat [3]
2 years ago
15

How many 4/5are in 1

Mathematics
2 answers:
OverLord2011 [107]2 years ago
6 0

Answer:

If your gonna ask it on groups its one group

natita [175]2 years ago
3 0
There are one 4/5 in 1 cus (1=5/5)
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Use the distributive property to rewrite 1/4 (x - 16)
Gnesinka [82]

Answer: 1/4x - 4

May i have brainliest

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3 years ago
What is the answer to 2 + -1/3 =
Helga [31]
The answer is : 1:6 repeating
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3 years ago
What is the nth term?
kumpel [21]

Let a_k denote the <em>k</em>th term of the sequence. Then

a_k=a_1+d(k-1)

where <em>d</em> is the common difference between consecutive terms in the sequence and <em>a</em>₁ is the first term.

The sum of the first <em>n</em> terms is

S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n

From the formula for a_k, we get

S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)

S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k

S_n=na_1+\dfrac{d(n-1)n}2

S_n=\dfrac n2(2a_1-d+dn)

So we have d=-5, and 2a_1-d=16 so that a_1=\frac{11}2.

Then the <em>n</em>th term in the sequence is

a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}

7 0
3 years ago
Write the fraction as a equivalent fraction with a common denominator of 0.55
AnnZ [28]

Answer: 11/20

Step-by-step explanation:

55/100

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common denominator of 55? wdym. like the bottom number 55?

6 0
3 years ago
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Simplify the expression x^5 • x^7
iragen [17]

Answer:

\Huge\boxed{\mathsf{\Rightarrow X^1^2}}

Step-by-step explanation:

<h3><u>TO SOLVE:</u></h3>

With exponent rule.

<h3><u>SOLUTIONS:</u></h3>

First, use exponent rule.

<u><em>EXPONENT RULE:</em></u>

<u><em /></u>

\displaystyle \mathsf{\Rightarrow A^B*A^C=A^B^+^C}}

\displaystyle \mathsf{X^5^+^7}}

Solve.

Add the numbers from left to right.

\displaystyle \mathsf{7+5=\boxed{\mathsf{\Rightarrow 12}}}}

\Rightarrow \Large \boxed{\mathsf{X^1^2}}}

So, the final answer is x¹².

7 0
3 years ago
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