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IrinaVladis [17]

3 years ago

6

The cost for 4 hours of math tutoring is 186. The cost for 24 hours is 1001. Write a linear equation to find the total cost “C”

for “H” hours. Use the equation to find 19 hours

1 answer:

Dvinal [7]3 years ago

8 0

so if 4 hours of math is 186, one hour is 46.5, therefore when you write a liner equation, you start with y=46.5x and then multiply 19 by 46.5

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Mkey [24]

Part A:

Given that

$0.8x=1.6y\Rightarrow x= \frac{1.6}{0.8} y=2y$

Thus, x = ky where k = 2.

Therefore, the given equation is a direct variation.

Part B:

If y varies directly as x, then y = kx.

Given that y = 5 when x = 2, then

$5=2k \\ \\ \Rightarrow k=\frac{5}{2} =2.5 \\ \\ \Rightarrow y=2.5x$

When x = 12, y = 2.5(12) = 30.

Part C:

If y varies directly as x, then y = kx.

Given that y = 9 when x = -6, then

$9=-6k \\ \\ \Rightarrow k=-\frac{9}{6} =-\frac{3}{2} \\ \\ \Rightarrow y=-\frac{3}{2}x$

It can be seen that the equation above satisfies all the rows of the given table, therefore, y varies with x for the data in the question and the equation for the direct variation is $y=-\frac{3}{2}x$

Part 4:

If y varies directly as x, then y = kx.

Given that y = 1 when x = -2, then

$1=-2k \\ \\ \Rightarrow k=-\frac{1}{2} \\ \\ \Rightarrow y=-\frac{1}{2}x$

It can be seen that the equation above does not satisfies the other rows of the given table, therefore, y does not vary with x for the data in the question.

8 0

3 years ago

Read 2 more answers

How much will he pay for?

motikmotik

Answer:

$14.25 is the answer but to clear things up it is $2.25 for a bag of pop corn and $1.50 for a soda 5x2.25= 11.25 2x1.50=3 ,3+11.25=$14.25. and you can check that by using the amount for the pop corn and the soda in the first 2 equations :)

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Step-by-step explanation:

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6 0

2 years ago

The amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a stan

Ber [7]

Answer:

When sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

Step-by-step explanation:

We are given the amounts of time employees at a large corporation work each day are normally distributed, with a mean of 7.5 hours and a standard deviation of 0.35 hour.

Random samples of size 23 and 35 are drawn from the population and the mean of each sample is determined.

Here, $\mu$ = population mean = 7.5 hours

$\sigma$ = population standard deviation = 0.35 hour

<u><em /></u>

<u><em>Let </em></u> $\bar X$ <u><em> = sample mean</em></u>

(a) The random samples of size of n = 23 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $\frac{0.35}{23}$ = 0.073

(b) The random samples of size of n = 35 is drawn from the population;

So, mean of the distribution of sample means = $\mu$ = 7.5 hours

Standard deviation for the distribution of sample means is given by;

s = $\frac{\sigma}{\sqrt{n} }$ = $} \frac{0.35}{\sqrt{35} }$ = 0.059

(c) So, as we can see that when sample size increases from n = 23 to n = 35, the mean of the distribution of sample means remains same but the standard deviation of the distribution of sample means decreases from 0.073 to 0.059.

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3 years ago

I’ll give brianliest to anyone who can help me.

goldfiish [28.3K]

Answer:

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Step-by-step explanation:

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2 years ago