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Lapatulllka [165]
2 years ago
11

Write an equation for each translation of Y=|x|.

Mathematics
1 answer:
Digiron [165]2 years ago
6 0

\boxed{y=\mid x \mid +14}

<h2>Explanation:</h2>

Let's graph the equation:

y=\mid x \mid

Which is the red graph shown below. As you can see this is the pattern of the Absolute Value Function. In order to translate this graph 14 units up, let's add 14 to \mid x \mid. In doing so we get the new function:

y=\mid x \mid + 14

So we get a new graph which is the blue one. In order to prove that this is the correct translation, let's take the vertex of the red graph which is the origin. To translate this graph 14 units up implies that each point is shifted 14 units up, so for the vertex of the red graph:

Vertex \ of \ the \ red \ graph: \\ \\ V(0,0) \\ \\ \\ Vertex \ of \ the \ new \ graph: \\ \\ (0,0+14) \\ \\ (0,14)

So the new vertex matches the vertex of the blue graph. Finally, the equation for the translation of y=\mid x \mid 14 units up is y=\mid x \mid +14

<h2>Learn more:</h2>

Horizontal and vertical shift: brainly.com/question/13774447#

#LearnWithBrainly

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8<br> p varies directly as the square root of q.<br> p = 8 when q = 25.<br> Find p when q = 100.
Lostsunrise [7]

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16

Step-by-step explanation:

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2 years ago
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
2 years ago
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