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Alecsey [184]
3 years ago
5

I need to solve this equation

Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0
The answer is 18
x=18
tester [92]3 years ago
5 0
X/3 + 6 + 5x/6 = 27

Add x/3 with 5x/6.

x/3 + 5x/6 = ?

x/3 × 2/2 = 2x / 6

So, 2x/6 + 5x/6 = 7x/6

So, we now have :
 
7x/6 + 6 = 27

Subtract 6 from both sides.

7x/6 = 27 - 6

Simplify.

7x/6 = 21

Multiply 6 to both sides.

7x = 21 × 6

Simplify.

7x = 126

Divide both sides by 7.

x = 18

~Hope I helped!~
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The graph below describes the journey of a train between two cities.
Veseljchak [2.6K]

Answer:

[A] Acceleration in first 15 min = 200  km/h²

[B] Distance between two cities = 125 km

[C] Average Speed of journey =  62.5  km/hr

Step-by-step explanation:

To Solve:

Acceleration in first 15 min

Distance between two cities  

Average speed of journey

Solve:

[A] Work out the acceleration, in km/h?, in the first 15 mins.

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                     Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Hence, Answer for [A] = 200  km/h²

[B] Work out the distance between the two cities. $60 Velocity (in km/h)

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

[C] Work out the average speed of the train during 20 the journey.

Average Speed of journey = 125/2  = 62.5  km/hr

[RevyBreeze]

5 0
2 years ago
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