Answer:
12 unit²
Step-by-step explanation:
area ΔAMC = 1/2 CM x AH' = 1/4 BC x AH'
area ΔABM = 1/2 BM x AH' = 1/4 BC x AH'
area ΔAMC = area ΔABM
for the same calculation, we can prove
area ΔACN = area ΔDCN
area ΔAMC + area ΔACN = 6
area ΔABM + area ΔDCN = 6
ABCD = area ΔAMC + area ΔACN + area ΔABM + area ΔDCN = 6 = 6 = 12
The top equation, 3x+y-3=0.
When x is 0, y is 3 (also seen in graph).
When y is 0, x is 1.
6x-5=4x+5
+5
6x=4x + 0
-4x
2x=0
x =0
probably to late but whatever
1/4 (6x+2) - 3x= -1/2 - 4 +2x
-1/4 (6x+2) +3x= -1/4 -4 +3x
(6x+2) = -3/4 + 5x .
x = 10/7
Answer: 110 square cm
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Explanation:
All sides of a regular polygon are the same length. So the bottom side is also 8 cm.
Draw lines from the center to each vertex of the pentagon. Five triangles form. Each triangle has a base of 8 and a height of 5.5 (since all five triangles are congruent)
area of one triangle = 0.5*base*height = 0.5*8*5.5 = 22
area of five triangles = 5*(area of one triangle) = 5*22 = 110
