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2 years ago

One angle is 36 Degrees. What is the measure of its complement?

Mathematics

1 answer:

Andre45 [30]2 years ago

4 0

Complementary angles equal 90°

So 90-36= 54°

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Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

7 months ago

What is the answer???

Greeley [361]

Answer:

Angles in ascending order:

Q, R, S

Step-by-step explanation:

The side with the biggest number also has the biggest angle degree. The side with the smallest number also has the smallest angle degree.

6 0

3 years ago

Read 2 more answers

Carlos deposited $28.50 into his bank account after making a $20.00 withdrawal to pay for some school supplies, Represent these

Rama09 [41]

-$20.00
+$28.50
=$8.50

7 0

3 years ago

The starting and stopping point for Amir’s run this morning are 0.5 inch apart on the map. If each inch on the map represents 3

Aleonysh [2.5K]

Amir ran 1.5 miles in the morning.

7 0

2 years ago

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Find the limit. (If an answer does not exist, enter DNE.) lim Δx→0 (x + Δx)2 − 3(x + Δx) + 2 − (x2 − 3x + 2) Δx

yawa3891 [41]

$\displaystyle\lim_{\Delta x\to0}\frac{(x+\Delta x)^2-3(x+\Delta x)+2-(x^2-3x+2)}{\Delta x}$

Expand the numerator as

$x^2+2x\Delta x+(\Delta x)^2-3x-3\Delta x+2-x^2+3x-2=(2x-3)\Delta x+(\Delta x)^2$

Then in the limit,

$\displaystyle\lim_{\Delta x\to0}\frac{(2x-3)\Delta x+(\Delta x)^2}{\Delta x}=\lim_{\Delta x\to0}(2x-3+\Delta x)=\boxed{2x-3}$

3 0

2 years ago