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goldfiish [28.3K]
3 years ago
8

Jason and David went hiking at different times. Jason is currently 54 feet above sea level while David is starting at 11 feet be

low sea level. What is the difference in their elevations? (Hint: Use the distance equation or draw a number line.
Mathematics
1 answer:
tatuchka [14]3 years ago
3 0
Since jason is currently at 54 feet above sea level and David is 11 feet below sea level the add 11 plus 54 which would give you 65 feet is there distance of elevations
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Step-by-step explanation:

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5q + (22 - 13)

2) Simplify.

5q + 9

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Answer:

The matrix form of given linear system is

\begin{bmatrix}x'\\ y'\\ z'\end{bmatrix}=\begin{bmatrix}-8 & 7 &-9\\ 5 & -1 & 0\\ 10 & 7 & 8\end{bmatrix}\begin{bmatrix}x\\ y\\ z\end{bmatrix}

Step-by-step explanation:

Let as assume that

X=\begin{bmatrix}x\\ y\\ z\end{bmatrix}

Given differential equations are

\frac{dx}{dt}=-8x+7y-9z

\frac{dy}{dt}=5x-y

\frac{dz}{dt}=10x+7y+8z

We need to find the matrix form of given linear system.

Write the elements of left side in a column matrix.

Write all the coefficients in one matrix first which is called a coefficient matrix.  Multiply coefficient matrix with the variables matrix and equate left and right side.

\begin{bmatrix}\frac{dx}{dt}\\ \frac{dy}{dt}\\ \frac{dz}{dt}\end{bmatrix}=\begin{bmatrix}-8 & 7 &-9\\ 5 & -1 & 0\\ 10 & 7 & 8\end{bmatrix}\begin{bmatrix}x\\ y\\ z\end{bmatrix}

It can be written as

\begin{bmatrix}x'\\ y'\\ z'\end{bmatrix}=\begin{bmatrix}-8 & 7 &-9\\ 5 & -1 & 0\\ 10 & 7 & 8\end{bmatrix}\begin{bmatrix}x\\ y\\ z\end{bmatrix}

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