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Valentin [98]
3 years ago
11

Tia, Leah, and Tim all solve the problem 3(-x + 4) = -3x - 12. Tia solved and decided that the solution is x= 4. Leah solved the

equation and said that there are no solutions to the equation. Tim solved and said that there are infinitely many solutions. Who do you agree with?
Mathematics
1 answer:
nexus9112 [7]3 years ago
5 0

Answer:

Tina

Step-by-step explanation:

bc if you sub in 4 for x the equations on both sides are 0

check:

-4 + 4 = 0                         -3 x 4 = -12

0 x 3 = 0                          12 + -12 = 0

                    0 = 0

please mark this as brainiest!!!!

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kondaur [170]
I forgot that but good luck
7 0
3 years ago
Ginny is studying a population of frogs. She determines that the population is decreasing at an average rate of 3% per year. Whe
svp [43]

Answer:

Step-by-step explanation:

This is exponential, of the form

y=a(b)^x where a is the initial amount and b is the growth/decay rate. If Ginny begins the study with 1200 frogs in the population, our a value is 1200.

If the population is decreasing 3% per year, it is decreasing 100% - 3% = 97% which, as a decimal, is .97. Our exponential function, then, is

y=1200(.97)^x

6 0
3 years ago
Chnstopher earned $142.20. He saved $24.50. He spent the rest on 2 new pairs
pogonyaev

Answer:

$58.25

Step-by-step explanation:

142.20 - 24.50 = 117.50

117.50 / 2 = 58.25

6 0
4 years ago
Read 2 more answers
3 (a) Simplify e+ es
ANEK [815]

Answer:

I don't understand your question but here's some sample of simplify

Step-by-step explanation:

Simplify –(46x2y3z)0

The parenthetical portion still simplifies to 1, but this time the "minus" is out in front of the parentheses; that is, it's out from under the power, so the exponent doesn't touch it. So the answer in this case is:

–(46x2y3z)0 = –1

7 0
3 years ago
Find two unit vectos that are orthogonal to both [0,1,2] and [1,-2,3]
alekssr [168]

Answer:

Let the vectors be

a = [0, 1, 2] and

b = [1, -2, 3]

( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.

Let the cross product be another vector c.

To find the cross product (c) of a and b, we have

\left[\begin{array}{ccc}i&j&k\\0&1&2\\1&-2&3\end{array}\right]

c = i(3 + 4) - j(0 - 2) + k(0 - 1)

c = 7i + 2j - k

c = [7, 2, -1]

( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:

c / | c |

Where | c | = √ (7)² + (2)² + (-1)²  = 3√6

Therefore, the unit vector is

\frac{[7,2,-1]}{3\sqrt{6} }

or

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

In conclusion, the two unit vectors are;

[ \frac{7}{3\sqrt{6} } , \frac{2}{3\sqrt{6} } , \frac{-1}{3\sqrt{6} } ]

and

[ \frac{-7}{3\sqrt{6} } , \frac{-2}{3\sqrt{6} } , \frac{1}{3\sqrt{6} } ]

<em>Hope this helps!</em>

7 0
3 years ago
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