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Valentin [98]
3 years ago
11

Tia, Leah, and Tim all solve the problem 3(-x + 4) = -3x - 12. Tia solved and decided that the solution is x= 4. Leah solved the

equation and said that there are no solutions to the equation. Tim solved and said that there are infinitely many solutions. Who do you agree with?
Mathematics
1 answer:
nexus9112 [7]3 years ago
5 0

Answer:

Tina

Step-by-step explanation:

bc if you sub in 4 for x the equations on both sides are 0

check:

-4 + 4 = 0                         -3 x 4 = -12

0 x 3 = 0                          12 + -12 = 0

                    0 = 0

please mark this as brainiest!!!!

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Answer:

The second and fourth one

6 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!
Lelechka [254]

Answer:

Step-by-step explanation:

(8x²-18x+10)/(x²+5)(x-3)

express the expression as a partial fraction:

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +bx+c/x²+5

both denominator are equal , so require only work with the nominator

(8x²-18x+10)=(x²+5)A+(x-3)(bx+c)

8x²-18x+10= x²A+5A+bx²+cx-3bx-3c

combine like terms:

x²(A+b)+x(-3b+c)+5A-3c

(8x²-18x+10)

looking at the equation

A+b=8

-3b+c=-18

5A-3c=10

solve for A,b and c (system of equation)

A=2 , B=6, and C=0

substitute in the value of A, b and c

(8x²-18x+10)/[(x^2+5)(x-3)] =A/x-3 +(bx+c)/x²+5

(8x²-18x+10)/[(x^2+5)(x-3)] = 2/x-3 + (6x+0)/(x²+5)

(8x²-18x+10)/[(x^2+5)(x-3)] =

<h2>2/(x-3)+6x/x²+5</h2>

(4x+2)/[(x²+4)(x-2)]

(4x+2)/[(x²+4)(x-2)]= A/(x-2) + bx+c/(x²-2)

(4x+2)=a(x²-2)+(bx+c)(x-2)

follow the same step in the previous answer:

the answer is :

<h2>(4x+2)/[(x²+4)(x-2)]= 5/4/(x-2) + (3/2 -5x/4)/(x²+4)</h2>

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Step-by-step explanation:

i did the math, that answer should be correct, but the question is stated  strange.

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Answer:

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Step-by-step explanation:

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What are the points of intersection of -x^2+9x-3 and y=3x
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Step-by-step explanation:

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