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Annette [7]
3 years ago
7

At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperatures is 50\degree50°50,

degree Celsius. This causes the cake to cool and the temperature difference loses \dfrac15 5 1 ​ start fraction, 1, divided by, 5, end fraction of its value every minute.
Mathematics
1 answer:
MrRissso [65]3 years ago
7 0

D(t)=50^o(0.80)^t

<u>Step-by-step explanation</u>:

Writing a function that gives the temperature difference in degrees Celsius, D(t), t minutes after the cake was put in the cooler

we know that

The equation of an exponential decay function is equal to

D(t) = a(1 - r )^{t}

where

                D(t) is the temperature difference in degrees

                 t is the number of minutes

                 r is the rate of change

                 a is the initial value

we have

a = 50°C

r = 1 / 5 = 0.20

substitute

D(t) = 50° (1 - 0.20)^{t}

D(t) = 50° (0.80)^{t}

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