Total distance 5 km; at 5km / 0.65 h =
Second part distance: x; at 6 km/h, during t2
First part distance: 5 - x; at 8.75 km/h, during t1
V = d/t ⇒ t = d/V
t2 = x/6
t1=[5-x]/8.75
t2 + t1 = 0.65
x/6 + [5-x]/8.75 = 0.65
x/6 + 5/8.75 - x/8.75 = 13/20
x/6 - x/8.75 = 13/20 - 5/8.75
x/6 - 4x/35 =13/20 - 20/35
35x - 24x = (35*6)(35*13 - 20*20)/(20*35)
11 x = 16.5
x = 16.5/11 = 1.5 km
Answer:
b
Step-by-step explanation:
make a formula, its the easiest way to solve problems like these also its very efficent
Answer:
B
Step-by-step explanation:
recall that point-slope form of a linear equation is expressed as follows
y - y1 = m (x - x1)
where m = slope and (x1, y1) is the coordinate of any point on the line
so, here we have m = (3/5), x1 = 4 and y1 = -6
substitute these into the formula
y - (-6) = (3/5) (x - 4)
y + 6 = (3/5) (x - 4)----> answer
Answer:
the 2
Step-by-step explanation:
