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Snezhnost [94]
2 years ago
5

Is the following relationship a function?

Mathematics
2 answers:
mylen [45]2 years ago
4 0

Answer:

yes it's a inverse function

Otrada [13]2 years ago
4 0

Answer:

Yes it is

Step-by-step explanation:

To remeber, if none of the lines overlap or crosses each other, its a function.

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GD= ________ <br> please help lol
evablogger [386]
GD will equal 11. Because 22/2 is equal to 11
4 0
2 years ago
1. What is the slope and y-intercept of y=-3x - 2?
Nadya [2.5K]

Answer: The equation is y=mx+b where m is the slope and b is the intercept, so for your problem slope is 3 and the intercept is -2

Step-by-step explanation:

6 0
3 years ago
Urgent ;<br>if a^3+b^3=11 and a^3-b^3=5, evaluate a^6-b^6
11111nata11111 [884]

Factorize using the difference of squares identity.

a^6 - b^6 = \left(a^3\right)^2 - \left(b^3\right)^2 = \left(a^3 - b^3\right) \left(a^3 + b^3\right)

Then

a^6 - b^6 = 11 \cdot 5 = \boxed{55}

5 0
1 year ago
The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.
Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m  + 40 m  + c = 120 m

61 m +  c = 120 m

c = 120 m - 61 m

c = 59 m

                         B

                     ↓            ↓  

                  ↓                          ↓

                ↓                                       ↓

            A →  →  → →  →  → →  → →    →    →  C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0

Angle B is calculated as follows;

Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0

Angle C is calculated as follows;

Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0

Therefore, the largest angle of the field is 149⁰.

       

8 0
3 years ago
Xpressions
zlopas [31]
you do parentheses first so 32-8=24
4+2=6



answer 24=6
8 0
2 years ago
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