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lorasvet [3.4K]
3 years ago
13

Give an example question ( use words and numbers)

Mathematics
1 answer:
Ymorist [56]3 years ago
8 0
A 2 - - 7 = 9
b - 3 - - 4 = 1
c - 5 - 6 = - 11
d - 3 - - 5 = 2
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(a) What is the actual cost incurred in producing the 1051st and the 2191st disc? (Round your answers to the nearest cent.)
Evgen [1.6K]

This question is incomplete, the complete question is;

The total weekly cost (in dollars) incurred by Lincoln Records in pressing x compact discs is given by the following function;

C(x) = 2000 + 2x -0.0001x²  (0 ≤ x ≤ 6000) .

(a) What is the actual cost incurred in producing the 1051st and the 2191st disc? (Round your answers to the nearest cent.)

(b) What is the marginal cost when x = 1050 and 2190? (Round your answers to the nearest cent.)

Answer:

a)

Actual cost for 1051st disc is $1.79

Actual cost for 2191st disc is $1.56

b)

the marginal cost are;

C'(1050) = $1.79

C'(2190) =  $1.56

Step-by-step explanation:

Given the data in the question;

C(x) = 2000 + 2x -0.0001x²

a)

What is the actual cost incurred in producing the 1051st and the 2191st disc? (Round your answers to the nearest cent.)

Actual cost for 1051st disc will be;

⇒ C(1051) - C(1050)  

= [ 2000 + 2(1051) - 0.0001×(1051)²] - [ 2000 + 2(1050) - 0.0001×(1050)² ]

= [ 2000 + 2102 - 110.4601 ] - [ 2000 + 2100 - 110.25 =

= 3991.5399 - 3989.75

= $ 1.7899 ≈ $1.79

Actual cost for 2191st disc will be;

⇒ C(2191) - C(2190)  

= [ 2000 + 2(2191) - 0.0001×(2191)²] - [ 2000 + 2(2190) - 0.0001×(2190)² ]

= [ 2000 + 4382 - 480.0481 ] - [ 2000 + 4380 - 479.61 ]

= 5901.9519 - 5900.39

= $ 1.5619 ≈ $1.56

Therefore,

Actual cost for 1051st disc is $1.79

Actual cost for 2191st disc is $1.56

b)

What is the marginal cost when x = 1050 and 2190? (Round your answers to the nearest cent.)

Marginal cost is; C'(x) = 2 - 0.0002x

so;

C'(1050) = 2 - 0.0002(1050) = 2 - 0.21 = $1.79

C'(2190) = 2 - 0.0002(2190) = 2 - 0.438 = $1.562 ≈ $1.56

Therefore; the marginal cost is;

C'(1050) = $1.79

C'(2190) =  $1.56

3 0
3 years ago
2 grey cards
denis-greek [22]
  • P(G)=2
  • P(Y)=7
  • P(P)=5

Now

  • Total=E=7+5+2=12+2=14

Now

  • P(G')=14-2=12

Probability of not selecting gray =12/14

Now

But pink is in 5

  • P(P)=5/12
5 0
2 years ago
What’s the product of 0.54(8)
maw [93]

The answer to your problem is 4.32.

6 0
3 years ago
Which function is increasing?
DerKrebs [107]

Answer:

A, it's the only one with a number greater then 1

5 0
3 years ago
Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce
pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0
3 years ago
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