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lorasvet [3.4K]

3 years ago

13

Give an example question ( use words and numbers)

1 answer:

Ymorist [56]3 years ago

8 0

A 2 - - 7 = 9
b - 3 - - 4 = 1
c - 5 - 6 = - 11
d - 3 - - 5 = 2

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ASAP PLZZZZZZZ ANSWER RIGHT

Darina [25.2K]

Answer: ALZ is congruent to AIR by reason ASA

Step by Step Explanation: i hate rsm

8 0

3 years ago

Charles bought 7/8 foot of electrical wire and 5/6 foot of copper wire for his science project .What is the least common denomin

coldgirl [10]

Answer:

The least common denominator of the fractions is 24

Step-by-step explanation:

we know that

The <u>least common denominator</u> (LCD) is the smallest number that can be a common denominator for a set of fractions

so

we have

7/8

Multiples of 8 -------> 8,16,24,32,...

5/6

Multiples of 6 -------> 6,12,18,24,...

24 is a common multiple of 6 and 8. It is their lowest common multiple

<em>Alternative Method</em>

we have

$8=2^{3}$

$6=2*3$

The least common multiple are those common and non-common numbers with the greatest exponent

so

$lcm= 2^{3}*3=24$

6 0

3 years ago

X/4 -3 = 1/3 + 2x solve for x

ivann1987 [24]

Answer:

Step-by-step explanation:

$\frac{x}{4}$ - 3 = $\frac{1}{3}$ + 2x ...... <em>(1)</em>

(1) × 12 :

3x - 36 = 4 + 24x

21x = - 40

x = - $\frac{40}{21}$ = $-1\frac{19}{21}$

4 0

2 years ago

A student solves the following equation and

Phoenix [80]

Answer:

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

Step-by-step explanation:

Considering the expression

$\frac{3}{a+2}-6\cdot \frac{a}{-4+a^2}=\frac{1}{a-2}$

$\frac{3}{a+2}-\frac{6a}{-4+a^2}=\frac{1}{a-2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}a+2,\:-4+a^2,\:a-2:\quad \left(a+2\right)\left(a-2\right)$

$\mathrm{Multiply\:by\:LCM=}\left(a+2\right)\left(a-2\right)$

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right)-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right)=\frac{1}{a-2}\left(a+2\right)\left(a-2\right)$

as

$\frac{3}{a+2}\left(a+2\right)\left(a-2\right):\quad 3\left(a-2\right)$

$-\frac{6a}{-4+a^2}\left(a+2\right)\left(a-2\right):\quad -6a$

$\frac{1}{a-2}\left(a+2\right)\left(a-2\right):\quad a+2$

so equation becomes

$3\left(a-2\right)-6a=a+2$

$-3a-6=a+2$

$-3a-6+6=a+2+6$

$-4a=8$

$\mathrm{Divide\:both\:sides\:by\:}-4$

$\frac{-4a}{-4}=\frac{8}{-4}$

$a=-2$

$\mathrm{Verify\:Solutions}$

$\mathrm{Take\:the\:denominator\left(s\right)\:of\:}\frac{3}{a+2}-6\frac{a}{-4+a^2}-\frac{1}{a-2}\mathrm{\:and\:compare\:to\:zero}$

$\mathrm{Solve\:}\:a+2=0:\quad a=-2$

$\mathrm{Solve\:}\:-4+a^2=0:\quad a=2,\:a=-2$

$\mathrm{Solve\:}\:a-2=0:\quad a=2$

So the following points are undefined

$a=-2,\:a=2$

Since the equation is undefined for -2

Therefore, NO SOLUTION for the given equation.

4 0

3 years ago

there were 260 students enrolled in a school last year and 40 teachers employed by the same school. this year the number of stud

tatiyna

The percentage change would be 4%

7 0

3 years ago