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Alexandra [31]
3 years ago
12

Can someone plz help me solved this problem I need help plz help me! Will mark you as brainiest!

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer: x^2 -3

That's x squared minus three

Step-by-step explanation:

When you divide 2x^3 by 2x the 2's cancel, and x cubed becomes x squared.

In 6x divided by 2x, the X's cancel and 6 ÷2=3

BTW "cancels" means that a number divided by itself equals one, so it "disappears" from the expression

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Whats the answer for 6n+7-2n-14=5n-1​
12345 [234]

Answer:

Simplifying

6n + 7 + -2n + -14 = 5n + 1

Reorder the terms:

7 + -14 + 6n + -2n = 5n + 1

Combine like terms: 7 + -14 = -7

-7 + 6n + -2n = 5n + 1

Combine like terms: 6n + -2n = 4n

-7 + 4n = 5n + 1

Reorder the terms:

-7 + 4n = 1 + 5n

Solving

-7 + 4n = 1 + 5n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-5n' to each side of the equation.

-7 + 4n + -5n = 1 + 5n + -5n

Combine like terms: 4n + -5n = -1n

-7 + -1n = 1 + 5n + -5n

Combine like terms: 5n + -5n = 0

-7 + -1n = 1 + 0

-7 + -1n = 1

Add '7' to each side of the equation.

-7 + 7 + -1n = 1 + 7

Combine like terms: -7 + 7 = 0

0 + -1n = 1 + 7

-1n = 1 + 7

Combine like terms: 1 + 7 = 8

-1n = 8

Divide each side by '-1'.

n = -8

Simplifying

n = -8

Step-by-step explanation:

6 0
2 years ago
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In the figures below, the cube-shaped box is 6 inches wide and the rectangular box is 10 inches long, 4 inches wide, and 4 inche
11111nata11111 [884]
The difference in volume= v^{3} -V*L*H
=6^{3}-(10*4*4)
=216-160
= 56 cubic inches
4 0
3 years ago
Please help me What is the midpoint of a line segment with the endpoints (4, -3) and (7,-5)?
liq [111]

Answer:

(11/2, -1)

Step-by-step explanation:

7 0
2 years ago
Identify the common factor of 16,24,50
goldenfox [79]
The common factor is 2
5 0
3 years ago
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Iodine-125 has a half-life of about 60 days. How many milligrams of a 500 mg sample will remain after 300 days?
just olya [345]

60 x 5 = 300 days

So five half-lifes = 300 days

Starting amount = 500mg

<span>Amount after 1st half-life = 250 mg</span>

<span>Amount after 2nd half-life = 125 mg</span>

<span>Amount after 3rd half-life = 62.5 mg</span>

<span>Amount after 4th half-life = 31.25 mg</span>

<span>Amount after 5th half-life = 15.625 mg</span>

<span>Hence after 300 days, the amount of iodine-125 will be 15.625 mg out of 500 mg.</span>

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3 years ago
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