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icang [17]
4 years ago
13

Hi, my question is in the picture below :)

Mathematics
1 answer:
galina1969 [7]4 years ago
8 0
I hope this helps you

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The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with a mean of 1262 chips
Sholpan [36]

Answer:

Using z score formula:

X = z ∂ + µ

 = 157.833

Step-by-step explanation:

Solution:

Mean = µ = 1262

Standard deviation = ∂ = 117

(a) 28th percentile for the number of chocolate chip.

P( z < z) = 28%

             = 0.28

P( z<- 0.58)  = 0.28

Z = -0.58

By using z score formula:

Z = x - µ /∂

-0.58= x – 117 / 1262

X = (- 0.58)(117) + (1262)

 =  1194.14

(b) Middle 97% of bag.

P(-z < z < z) = 97%

                    = 0.97

P( z < z) – p(z < -z) = 0.97

2p(z < z) -1 = 0.97

2p (z < z) = 1 + 0.97

P(z < z) = 1.97 / 2

            = 0.99

P(z < 2.33) = 0.99

Z ± 2.33

By using z score formula:

Z = x - µ / ∂

X = z ∂ + µ

  = - 2.33 x 117 + 1262

  =989.39

Z = 2.33

X = z ∂ + µ

  =  2.33 x 117 + 1262

 =1533.61

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.

By using standard normal table,

The z dist’n formula:

P(z < z ) = 25%

            =0.25

P(z < -0.6745) = 0.25

Z = 0.6745

Using z score formula:

X = z∂ + µ

   = - 0.6745 x 117 + 1262

  = 1183.0835

First quartile = Q1 =1183.0835

The third quartile is:

P(z<z) = 75%

    = 0.75

P(z < 0.6745) = 0.75

Z = 0.6745

Using z score formula:

X = z ∂ + µ

  = 0.6745 x 117 + 1262

= 1340.9165

IQR = Q3 – Q1

     = 1340.9165 – 1183.0835

  = 157.833

3 0
3 years ago
Can anyone help me with this please
Novay_Z [31]
This is how the sketch should look on your graph!

8 0
4 years ago
Which best describes the function represented by the table?
trasher [3.6K]

Answer:

Option B is correct.

direct variation; k = 5/2

Step-by-step explanation:

The Direct variation says:

y \propto x

then the equation is of the form: y = kx   ......[1] where k is the constant of variation.

From the given table:

Consider x = -2 and y = -5

Substitute these in [1] to solve for k;

-5 = -2k

or

5 = 2k

Divide both sides by 2 we get;

k = \frac{5}{2}

⇒ the equation becomes: y = \frac{5}{2}x

Check:

Take x = 4 and y = 10;

y = \frac{5}{2}x

10 = \frac{5}{2} \times 4

10 = 5 \times 2

10 = 10  True

Therefore, the direct variation ; k = \frac{5}{2} best describe the function represented by the table

8 0
4 years ago
(05.06 LC)The net of an isosceles triangular prism is shown. What is the surface area, in square units, of the triangular prism?
Montano1993 [528]

Answer:

  • C. 152 units²

Step-by-step explanation:

Total surface area is the area of the net.

<u>The rectangles have area:</u>

  • 8*(5 + 6 + 5) = 128 units²

<u>The triangles have area:</u>

  • 2*(1/2*6*4) = 24 units²

<u>Total area is:</u>

  • 128 + 24 = 152 units²

Correct choice is C

5 0
3 years ago
Read 2 more answers
Please help ASAPppppppp
astraxan [27]

Answer:

206 miles more

Step-by-step explanation:

Divide 2240 and 28 and you get 280 then divide 2368 and 32 and subtract 280- 74

7 0
3 years ago
Read 2 more answers
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