Answer:
Using z score formula:
X = z ∂ + µ
= 157.833
Step-by-step explanation:
Solution:
Mean = µ = 1262
Standard deviation = ∂ = 117
(a) 28th percentile for the number of chocolate chip.
P( z < z) = 28%
= 0.28
P( z<- 0.58) = 0.28
Z = -0.58
By using z score formula:
Z = x - µ /∂
-0.58= x – 117 / 1262
X = (- 0.58)(117) + (1262)
= 1194.14
(b) Middle 97% of bag.
P(-z < z < z) = 97%
= 0.97
P( z < z) – p(z < -z) = 0.97
2p(z < z) -1 = 0.97
2p (z < z) = 1 + 0.97
P(z < z) = 1.97 / 2
= 0.99
P(z < 2.33) = 0.99
Z ± 2.33
By using z score formula:
Z = x - µ / ∂
X = z ∂ + µ
= - 2.33 x 117 + 1262
=989.39
Z = 2.33
X = z ∂ + µ
= 2.33 x 117 + 1262
=1533.61
(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate.
By using standard normal table,
The z dist’n formula:
P(z < z ) = 25%
=0.25
P(z < -0.6745) = 0.25
Z = 0.6745
Using z score formula:
X = z∂ + µ
= - 0.6745 x 117 + 1262
= 1183.0835
First quartile = Q1 =1183.0835
The third quartile is:
P(z<z) = 75%
= 0.75
P(z < 0.6745) = 0.75
Z = 0.6745
Using z score formula:
X = z ∂ + µ
= 0.6745 x 117 + 1262
= 1340.9165
IQR = Q3 – Q1
= 1340.9165 – 1183.0835
= 157.833
This is how the sketch should look on your graph!
Answer:
Option B is correct.
direct variation; k = 5/2
Step-by-step explanation:
The Direct variation says:
then the equation is of the form: 
......[1] where k is the constant of variation.
From the given table:
Consider x = -2 and y = -5
Substitute these in [1] to solve for k;
or
5 = 2k
Divide both sides by 2 we get;
⇒ the equation becomes: 
Check:
Take x = 4 and y = 10;
10 = 10 True
Therefore, the direct variation ; best describe the function represented by the table
Answer:
Step-by-step explanation:
Total surface area is the area of the net.
<u>The rectangles have area:</u>
- 8*(5 + 6 + 5) = 128 units²
<u>The triangles have area:</u>
<u>Total area is:</u>
Correct choice is C
Answer:
206 miles more
Step-by-step explanation:
Divide 2240 and 28 and you get 280 then divide 2368 and 32 and subtract 280- 74
