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navik [9.2K]
3 years ago
8

What set of reflections would carry trapezoid ABCD onto itself?

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
8 0

The <em><u>correct answer</u></em> is:

y=x, x-axis, y=x, y-axis

Explanation:

A reflection across the line y=x maps every point (x, y) to (y, x); it switches the coordinates but does not negate them.

This means for A(1, -1), we would have A'(-1, 1); B(2, -2)→B'(-2, 2); C(3, -2)→C'(-2, 3); and D(4, -1)→D'(-1, 4).

A reflection across the x-axis negates the y-coordinate; algebraically,

(x, y)→(-x, y).

This takes our new points A'(-1, 1)→A''(-1, -1); B'(-2, 2)→B''(-2, -2); C'(-2, 3)→C''(-2, -3); and D'(-1, 4)→D''(-1, -4).

Reflecting again across the line y=x will again switch the x- and y-coordinates:

A''(-1, -1)→A'''(-1, -1); B''(-2, -2)→B'''(-2, -2); C''(-2, -3)→C'''(-3, -2); and D''(-1, -4)→D'''(-4, -1).

Reflecting across the y-axis will negate the x-coordinate:

A'''(-1, -1)→(1, -1); B'''(-2, -2)→(2, -2); C'''(-3, -2)→(3, -2); and D'''(-4, -1)→(4, -1).

These are the same as our original points.

iren2701 [21]3 years ago
5 0
Answer: y = x, x-axis, y = x, y-axis

https://www.desmos.com/calculator/ike9geovzg
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2) Fill in an angle measure greater than 100 degrees for the missing angle in yellow below. You will fill
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Answer:

m∠a = 110°

m∠b = 110°

m∠c = 70°

m∠d = 70°

m∠i = 110°

m∠h = 110°

m∠j = 70°

m∠g = 110°

m∠f = 70°

m∠e = 70°

m∠k = 57°

m∠m = 70°

m∠l = 167°

Step-by-step explanation:

Let the measure of the yellow angle = 110°

Therefore;

m∠a = 110°  by vertically opposite angles

m∠b = m∠a = 110° by opposite interior angles of a parallelogram

m∠c = 180° - 110° = 70° by same side interior angles

m∠d = m∠c = 70° by opposite interior angles of a parallelogram

m∠i and m∠c are supplementary angles, therefore, m∠i = 110°

m∠h = m∠i = 110° by vertically opposite angles

m∠j = m∠c = 70° by vertically opposite angles

m∠g and m∠d are supplementary angles, therefore, m∠g = 110°

m∠f = m∠d = 70° by alternate interior angles

m∠f = m∠e = 70° by vertically opposite angles

m∠k = 180° - (m∠h + 13°) = 180° - (110° + 13°) = 57°

m∠b and m∠m are supplementary angles, therefore, m∠m = 70°

m∠l and 13° are supplementary angles, therefore, m∠l = 167°

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