Answer:
The answer is "2".
Explanation:
In the given question some information is missing, that is "The propagation time for satellite to earth" which is "270 milliseconds" so, the description to this question can be defined as follows:
Given values:
Bandwidth = 64 kbps
Data frames = 512 bytes
Propagation Time (tp ) =270 ms
Change Bandwidth kbps to bps:
1 kb= 1024 bytes
calculated bandwidth= 64 kbps = 64×1024 bps = 65536 bps
1 bytes = 8 bits
512 bytes = 512 × 8 = 4096 bits
Frame length = 4096 bits
Formula
Transmission time (Tt) = Frame length /Bandwidth
Window size = 1+2a
where a = Propagation time/Transmission time
Calculate Transmission time:
Transmission time (Tt) = 4096 / 65536
Transmission time (Tt)= 625 m.sec
Calculate Window size:
Window size = 1+2(270/625)
Window size
= 1+2(0.432)
Window size
= 1+0.864
Window size = 1.864
Window size
= 2
A router, possibly. Thought I'm not for sure because I'm not in computers and technology
Answer:
// program in C++.
// headres
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// array
int temperatures[7];
// count variable
int count=0;
cout<<"Enter the temperature of all days:";
for(int a=0;a<7;a++)
{
// read temperature of 7 days
cin>>temperatures[a];
// find temperature is extreme or not
if(temperatures[a]<-10||temperatures[a]>25)
// count
count++;
}
// print count of extreme temperature
cout<<"number of days of extreme temperature:"<<count<<endl;
return 0;
}
Explanation:
Create an array of size 7 to store the temperature of all days of week.Read the temperature of each day.If the temperature is less than -10 or greater than 25 then increment the count.This will count the number of days of extreme temperature.Print the count.
Output:
Enter the temperature of all days:-20 12 18 30 32 -15 15
number of days of extreme temperature:4