Answer:
Required code is given below.
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Explanation:
#include <stdio.h>
#include <string.h>
int main(void)
{
char input[100];
printf("Enter desired auto service:\n");
scanf ("%[^\n]%*c", input);
printf("You entered: %s\n",input);
if(strcmp(input,"Oil change") == 0){
printf("Cost of oil change: $35\n");
}
else if(strcmp(input,"Tire rotation") == 0){
printf("Cost of tire rotation: $19\n");
}
else if(strcmp(input,"Car wash") == 0){
printf("Cost of car wash: $7\n");
}
else{
printf("Error: Requested service is not recognized\n");
}
return 0;
}
OSHA (the Occupational Safety and Health Administration) is a part of the US Department of Labor that establishes, issues, and enforces national workplace safety regulatio…ns. These are designed to make job areas and practices safer for US workers.
SAP is a data and business processing platform.
Answer:
The program is written using PYTHON SCRIPT below;
N=int(input(" Enter number of Rows you want:"))
M=[] # this for storing the matrix
for i in range(N):
l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))
M.append(l)
print("The 2D Matrix is:\n")
for i in range(N):
print(end="\t")
print(M[i])
W=[] # to store the first non zero elemnt index
T=[] # to store that value is positive or negative
L=len(M[0])
for i in range(N):
for j in range(L):
if (M[i][j]==0):
continue
else:
W.append(j) # If the value is non zero append that postion to position list(W)
if(M[i][j]>0): #For checking it is positive or negative
T.append(+1)
else:
T.append(-1)
break
print()
print("The first Non Zero element List [W] : ",end="")
print(W)
print("Positive or Negative List [T] : ",end="")
print(T)
Explanation:
In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.
It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.
