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Zolol [24]
3 years ago
15

The principal of a large high school wants to know if students spend more than 1 hour doing homework per night, on average. To i

nvestigate, the principal surveys a random sample of 100 students and will perform a significance test using a significance level of 0.05.
What hypothesis should the principal test?
Mathematics
1 answer:
MrRissso [65]3 years ago
7 0

Answer:

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 1

Alternative hypothesis: \mu >1

And they wnat to use a sample size of n = 100 and a significance level of 0.05

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: \mu \leq 1

Alternative hypothesis: \mu >1

And they wnat to use a sample size of n = 100 and a significance level of 0.05

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Step-by-step explanation:

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3 years ago
Which is not an equation of the line going through (6, 7) and (2, –1)?
garri49 [273]
Answer - D.

you basically find the equation of the line first and eliminate the wrong answers...

Strategy:  before u do any of this, label your coordinates as (X1,Y1) and (X2,Y2) and u can choose any of ur points to be as x1 or x2 or y1 or y1...
basically, I'll choose (6,7) as (x1,y1) and (2,-1) as (x2,y2). SO,

First you have to  find the gradient (m) of the line.
  you do this by using the formula m = Y2-Y1 / X2-X1 (where '/' is division sign) ....
Put the numbers in their respective places and your gradient will be 2x. we put the x after our number to represent it as a gradient as the straight line formula is y = mx+c and you've found the m.
NOW.
use the formula Y-Y1=m(x-x1) to find the equation of the line.Again u can use any Y1 and X1 here but remember your m is 2

replace the digits and solve...Hopefully you'll get sth like this if you use the points (6,7):
Y-7 = 2(x-6) ....
y=2x-12+7...
Y=2x-5! <<<< this is your straight line equation!
Now all u gotta do is rearrange all your options into y = mx+c.
D. is incorrect as it gives us y=2x+5 and not y = 2x-5 unlike the others 
 

Hope you get it!




7 0
3 years ago
Which equation is true?
Dmitry_Shevchenko [17]

Answer:

I think it is the first one.

Step-by-step explanation:

I think that becuase it is equal.

3 0
3 years ago
PLEASE HELP ME ASAP I NEED HELP ITS DUE AT 11:59
ivanzaharov [21]

Answer:

When -8 is x then y = -29

When -4 is x then y = -17

When 4 is x then y = 7

When 6 is x then y = 13

Step-by-step explanation:

You simply substitute the numbers on the x row for x in the equation, then you solve the problem. (3 x -8) - 5, ect.

8 0
3 years ago
Find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.
amm1812

Answer:

V = \frac{8\pi}{3}

Step-by-step explanation:

For this case we are interested on the region shaded on the figure attached.

And we can find the volume with the method of rings.

The area on this case is given by:

A(x) = \pi [f(x)]^2 = \pi r^2 = \pi [3x]^2 = 9\pi x^2

And the volume is given by the following formula:

V= \int_{a}^b A(x) dx

For our case our limits are x=0 and x=2 so we have this:

V = \pi \int_{0}^{2} x^2 dx

And if we solve the integral we got this:

V= \pi [\frac{x^3}{3}]\Big|_0^{2}

And after evaluate we got this:

V=\pi [(\frac{8}{3} )-(\frac{0}{3} )]

V = \frac{8\pi}{3}

3 0
3 years ago
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