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Lesechka [4]
3 years ago
10

Ricardo finds an online site about the gas laws. The site shows the equation below for Charles’s law.

Chemistry
2 answers:
Sati [7]3 years ago
4 0

Answer:The symbol for T2 should be smaller than for T1 because if volume increases, then temperature should decrease.

Explanation:

solong [7]3 years ago
3 0

Answer:

D, The volume should be divided by temperature on each side of the equation.

Explanation:

I just finished it, can confirm.

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What is the mass of oxygen in 10.0 grams of water
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At what temperature would the volume of a gas be 0.550 L if it had a volume of 0.432 L at –20.0 o C?
Gnom [1K]
The temperature that  would  the volume of a gas  be 0.550l  if  it  had a volume of 0.432 L  at  -20.0  c is calculated  using the Charles law formula

that is   v1/T1=V2/T2
V1=0.550 l
t1=?
T2= -20 c +273 = 253 K
v2= 0.432 l

by  making T1  the subject of the formula  T1= V1T2/V2


T1=  (0.55lL x253)/  0.432 l = 322.11 K  or  322.11-273 = 49.11 C
8 0
3 years ago
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Answer:

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3 years ago
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135 Joules of heat are required to increase the temperature of 10.0 grams of an unknown metal from 25.0∘C to 40.0∘C:
Sever21 [200]

Answer:

270 Joules

Explanation:

The specific heat capacity equation will be used for this question i.e.

Q = m. c. ΔT

Where; Q = Amount of heat

m = mass of substance

C = specific heat capacity of

substance

ΔT = change in temperature

(Final temp - initial temp)

However, for this unknown metal, we need to find the specific heat first by saying; C = Q / mΔT

Q= 135J, C=?, m= 10g, ΔT = (40-25 = 15°C)

C = 135 / 15 × 10

C = 135/150

C = 0.9 J/g°C

If the specific heat capacity of the unknown metal is 0.9 J/g°C, then at a mass of 20.0g, and a ΔT of 15°C, the amount of heat needed is:

Q = m. c. ΔT

Q = 20 × 0.9 × (40-25)

Q = 18 × 15

Q = 270J

270 Joules of heat is needed to increase the temperature of 20g of the metal from 25 - 40°C

8 0
3 years ago
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