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2 years ago

Does the motion of the moon affects how we see it from Earth? *

Chemistry

1 answer:

irina [24]2 years ago

7 0

Yes that’s why we see it in different shapes all the time

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Volume of a cone is 200.96 what is the height of the cone

Sedaia [141]

Is it inches millimeters meters ?

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2 years ago

What is the name of the molecule shown below?

Nezavi [6.7K]

Answer:

B) Methanoic Acid

Explanation:

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2 years ago

Water is a source of ______________ for chemical reactions in cells.

S_A_V [24]

Answer:Electrolyte

Explanation:Electrolyte is a compound either in solution or in molten form that gets decomposed by thee passage if electricity through it. Water is polar,but a weak electrolyte, so in cells,water is used as an electrolyte

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2 years ago

3. A 3.455-g sample of a mixture was analyzed for barium ion by adding a small excess of sulfuric acid to an aqueous solution of

erik [133]

Answer:

$Ba\ percentage\ in\ Mass=4.8\%$

Explanation:

From the question we are told that:

Mass of mixture $m=3.455g$

Mass of Barium $m_b=0.2815g$

Equation of Reaction is given as

$Ba2+ + H2SO4 => BaSO4 + 2 H+$

Generally the equation for Moles of Barium is mathematically given by

Since

$Moles of Ba^{2+} = Moles of BaSO_4$

Therefore

$Moles of Ba^{2+} = \frac{mass}{molar mass of BaSO4}$

$Moles of Ba^{2+} = \frac{0.2815}{233.39}= 0.0012061 mol$

Generally the equation for Mass of Barium is mathematically given by

$Mass\ of\ Ba^{2+} = Moles * Molar mass of Ba^{2+}$

$Mass\ of\ Ba^{2+} = 0.0012061 * 137.33 = 0.1656 g$

Therefore

$Ba\ percentage\ in\ Mass = mass of Ba^{2+}/mass of sample * 100%$

$Ba\ percentage\ in\ Mass= \frac{0.1656}{ 3.455 }* 100%$

$Ba\ percentage\ in\ Mass=4.8\%$

8 0

2 years ago

We might think of a porous material as being a composite wherein one of the phases is a pore phase. Estimate upper and lower lim

eduard

Answer:

The upper and lower limits for the room-temperature thermal conductivity of a magnesium oxide material having a volume fraction of 0.10 of pores that are filled with still air are

Ku = 38.252 W/mK

K lower = 0.199 W/mK

Explanation:

As we know

Ku = Vp * Kair + Vmagnesium * K metal

Ku = 0.10 *0.02 + (1-0.25) * 51

Ku = 38.252 W/mK

The lower limit

K lower = Kmetal* Kair/( Vp * Kmetal + Vmetal * K air)

K lower = (0.02*51)/(0.10*51 + 0.90 * 0.02)

K lower = 0.199 W/mK

8 0

2 years ago