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Snezhnost [94]
3 years ago
14

Which sequence represents the correct ranking of the amount of nitrogen per molecule, from least to most nitrogen? Urea, uric ac

id, ammonia Uric acid, ammonia, urea Ammonia, urea, uric acid Ammonia, uric acid, urea
Chemistry
1 answer:
Reptile [31]3 years ago
5 0

Answer:

Ammonia, urea, uric acid

Explanation:

The given compounds are:-

Urea which has a molecular formula of CH_4N_2O and has 2 atoms of nitrogen per molecule.

Ammonia which has a molecular formula of NH_3 and has 1 atom of nitrogen per molecule.

Uric acid which has a molecular formula of C_5H_4N_4O_3 and has 4 atoms of nitrogen per molecule.

Thus,

The order from least to most nitrogen is:-

Ammonia, urea, uric acid

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lesya692 [45]

Answer:

Explanation:

The atomic number tell us the number of protons and neutrons in the nucleus of an atom. in other words ,each element has a unique number that identifies how many protons are in one atom of that element example, all hydrogen atoms, and only hydrogen atoms, contain one proton and have an atomic number of 1.

4 0
3 years ago
What is the IMA of the lever pictured?<br><br><br><br> 0.18<br> 0.20<br> 0.90<br> 5
IceJOKER [234]
<span>The ideal mechanical advantage represents the number of times the input force is multiplied under ideal conditions, that is with no friction. Actual mechanical advantage on the other hand stands for the number of times the input force is multiplied. 
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6 0
3 years ago
Read 2 more answers
2)
vodomira [7]

Answer:

Final volume 30.513 L.

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 17 L

Initial pressure = 2.3 atm

Initial temperature = 299 K

Final temperature = 350 K

Final volume = ?

Final pressure = 1.5 atm

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 2.3 atm × 17 L × 350 K / 299 K × 1.5 atm

V₂  =  13685 atm .L.  K  / 448.5 K . atm

V₂  = 30.513 L

6 0
3 years ago
Metals present in municipal wastewater may still be present in treated sewage sludge; ______
Marrrta [24]
Metals present in municipal waste water may still be present in treated sewage sludge IN CONCENTRATIONS THAT MAY AFFECT THE PUBLIC HEALTH. Sewage sludge is an end product of municipal waste water treatment and it contains many of the pollutant that are removed from the waste water. 
5 0
3 years ago
• We obtained the above 10.00-mL solution by diluting a stock solution using a 1.00-mL aliquot and placing it into a 25.00-mL vo
garik1379 [7]

Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) 0.0035 mole

c)  0.166 M

Explanation:

Phosphoric acid is tripotic because it has 3 acidic hydrogen atom surrounding it.

The equation of the reaction is expressed as:

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

1 mole         3 mole

The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b)  if 10.00 mL of a phosphoric acid solution required the addition of 17.50 mL of a 0.200 M NaOH(aq) to reach the endpoint; Then the molarity of the solution is calculated as follows

H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O

10 ml            17.50 ml

(x) M              0.200 M

Molarity = \frac{0.2*17.5}{1000}

= 0.0035 mole

c) What was the molar concentration of phosphoric acid in the original stock solution?

By stoichiometry, converting moles of NaOH to H₃PO₄; we have

= 0.0035 \ mole \ of NaOH* \frac{1 mole of H_3PO_4}{3 \ mole \ of \ NaOH}

= 0.00166 mole of H₃PO₄

Using the molarity equation to determine the molar concentration of phosphoric acid in the original stock solution; we have:

Molar Concentration =  \frac{mole \ \ of \ soulte }{ Volume \ of \ solution }

Molar Concentration = \frac{0.00166 \ mole \ of \  H_3PO_4 }{10}*1000

Molar Concentration = 0.166 M

∴  the molar concentration of phosphoric acid in the original stock solution = 0.166 M

6 0
3 years ago
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