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3 years ago

1) Evaluate the expression 9 - z when z= 4.

Mathematics

1 answer:

nevsk [136]3 years ago

7 0

9-4 = 5 If u have 9 apples and take away 4 you have 5 apples left

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Let p be the population proportion for the following condition. Find the point estimates for p and q. In a survey of 1226 adults

weeeeeb [17]

Answer:

(a)0.3303

(b)0.6697

Step-by-step explanation:

Point estimation is the use of sample data to calculate a single value which serves as a best estimate of a given unknown population parameter.

Total Sample=1226

Number who said that they were not confident that the food they eat in country A is safe=405.

The point estimate of those who said that they were not confident that the food they eat in country A is safe is given as $\^{p}$

(a)Point Estimate for p,

$\^{p}=\frac{405}{1226} =0.3303$

(b)Point estimate for q, $\^{q}=$ 1- (point estimate for p)

=1-0.3303

=0.6697

8 0

3 years ago

How many license plates can be made using either three digits followed by three uppercase english letters or three uppercase eng

sukhopar [10]

17576000 because you can use 26 letters so you multiply that by 3 and get 18576 and then you multiply that by 1000 to get the answer

5 0

3 years ago

2 11 pt 5n +3 = –2(1–7n)

Mkey [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

Distributive Property Using GCF 25 + 30

postnew [5]

Hey there! I'm happy to help!

Let's look at the factors of each of these numbers.

1,25

5,5

1,30

2,15

3,10

5,6

The greatest common factor between these is 5. Therefore, we divide 25+30 by 5 and put the 5 on the outside.

5(5+6).

This has the same value but it is just written differently.

Have a wonderful day! :D

3 0

3 years ago

Using addition formula solve tan 15

salantis [7]

Answer:

2 - $\sqrt{3}$

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = $\frac{tanA-tanB}{1+tanAtanB}$ and the exact values

tan45° = 1 , tan60° = $\sqrt{3}$ , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= $\frac{tan60-tan45}{1+tan60tan45}$

= $\frac{\sqrt{3}-1 }{1+\sqrt{3} }$

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + $\sqrt{3}$ is 1 - $\sqrt{3}$

= $\frac{(\sqrt{3}-1)(1-\sqrt{3}) }{(1+\sqrt{3})(1-\sqrt{3}) }$ ← expand numerator/denominator using FOIL

= $\frac{\sqrt{3}-3-1+\sqrt{3} }{1-3}$

= $\frac{-4+2\sqrt{3} }{-2}$

= $\frac{-4}{-2}$ + $\frac{2\sqrt{3} }{-2}$

= 2 - $\sqrt{3}$

3 0

3 years ago