Robot 1- W = 20(3m) W= 60Nm
Robot 2- W= 30N (3m), W = 90Nm
Robot 3- W= 10N(2m), W= 20Nm
Robot 4- W= 30N(2m), W= 60Nm
Robot 2 did the most work, Robot 3 did the least amount of work and Robots, 1 and 4 did an equal amount of work
Answer:
(i) The name of the part of the circle, OQ is a radius
(ii) The radius of the sector QOR is 21 cm
Step-by-step explanation:
The given figure is a sector of the circle O
∵ Any sector of a circle formed from 2 radii and an arc
∴ OQ is a radius
(i) The name of the part of the circle, OQ is a radius
The rule of the length of an arc of a circle is L =
× 2 π r, where
- α is the angle of the sector
- r is the radius of the circle
∵ The length of the arc QR is 22 cm
∴ L = 22
∵ The measure of the angle of the arc is 60°
∴ α = 60°
∵ π = 
→ Substitute them in the rule above
∵ 22 =
× 2 ×
× r
∴ 22 =
r
→ Divide both sides by 
∴ 21 = r
(ii) The radius of the sector QOR is 21 cm
<u>Parallel lines</u> are lines that run side-by-side without touching or intersecting!
<u>Perpendicular lines</u> intersect/cross and can also make 90° angles (those little green boxes in the picture) in their corners!
Sets of parallel lines:
Sets of perpendicular lines:
The answer is the third choic, or the line with the same slope.
Point-slope form: y-y1 = m(x-x1)
Standard form: ax + by = c
Slope-intercept form: y = mx+b
Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.
To create point-slope form, we need to get one point from the graph. Let's use (3,0).

To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

To get standard form, solve the equation in terms of C.
Point-slope form: y = -4/3(x-3)
Slope-intercept form: y = -4/3x + 4
Standard form: 4/3x + y = 4