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Ghella [55]
3 years ago
10

Write the equation of a line that has a slope of 5 and passes through the point (3,9)

Mathematics
1 answer:
labwork [276]3 years ago
8 0

Answer:

y - 9 = 5(x - 3)

Step-by-step explanation:

Here the point (h, k) is (3, 9), and the slope m is 5.  Substituting these values into the point-slope formula y - k = m(x - h), we get:

y - 9 = 5(x - 3)

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Can anyone help ? I need to answer it for my homework today
Rus_ich [418]
Robot 1- W = 20(3m) W= 60Nm
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5 0
3 years ago
Can anyone teach mee..................... ​
andrew11 [14]

Answer:

(i) The name of the part of the circle, OQ is a radius

(ii) The radius of the sector QOR is 21 cm

Step-by-step explanation:

The given figure is a sector of the circle O

∵ Any sector of a circle formed from 2 radii and an arc

∴ OQ is a radius

(i) The name of the part of the circle, OQ is a radius

The rule of the length of an arc of a circle is L = \frac{\alpha }{360} × 2 π r, where

  • α is the angle of the sector
  • r is the radius of the circle

∵ The length of the arc QR is 22 cm

∴ L = 22

∵ The measure of the angle of the arc is 60°

∴ α = 60°

∵ π = \frac{22}{7}

→ Substitute them in the rule above

∵ 22 = \frac{60}{360} × 2 × \frac{22}{7} × r

∴ 22 = \frac{22}{21} r

→ Divide both sides by  \frac{22}{21}

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5 0
2 years ago
What is all of this <br> Identify ALL sets of parallel and perpendicular lines in this image.
Tamiku [17]

<u>Parallel lines</u> are lines that run side-by-side without touching or intersecting!

<u>Perpendicular lines</u> intersect/cross and can also make 90° angles (those little green boxes in the picture) in their corners!

Sets of parallel lines:

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Sets of perpendicular lines:

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5 0
2 years ago
Which line is parallel to y= = 1/3x + 7?
Monica [59]
The answer is the third choic, or the line with the same slope.
8 0
3 years ago
Read 2 more answers
Can someone help me with these please?
saul85 [17]

Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b


Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.


To create point-slope form, we need to get one point from the graph. Let's use (3,0).

y = -\frac{4}{3}(x-3)


To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

y = -\frac{4}{3}x + 4


To get standard form, solve the equation in terms of C.


Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4



7 0
3 years ago
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