Find the constant rate of change.

I need how to solve this question?

Nesterboy [21]

Answer: #1 is 5 #2 is 17

4 0

3 years ago

Read 2 more answers

Solve 9x-7y=-7 i don't know how to do it so could you show me step by step please

Lesechka [4]

First of all, you need to know what a 'solution' is, so you'll know it
when you see it.

A 'solution' to an equation is a number, or a set of numbers, that
you can write in place of the variables (the letters), and when you
do that, the equation will have only numbers in it, and it'll be a true
statement.

Your equation has two variables in it ... 'x' and 'y' . In order to find
just a single set of numbers for what both of them must be, you
would need two equations.

The way it stands now, with only one equation, there are actually
an infinite number of solutions. Each solution is a pair of numbers ...
one for 'x' and one for 'y' ... and if you write them into the equation
in place of 'x' and 'y', then the equation is a true statement.
I'll show you how to tell if a pair of numbers is a solution or not.

Here's what that looks like:

Say I give you two pairs of numbers, and I tell you that both of them
are solutions to your equation. The 'solutions' I give you are

          x=0
          y=1
and
          x=2
          y=3 .

You don't trust me, and you say to me "Wait just a minute there, dude !
Not so fast. I'll need to check them out and see if those are really solutions
to my equation."

You take the first pair and write it into your equation:
x=1, y=0
           9x - 7y = -7
                    9(0) - 7(1) = -7
                     0    - 7   = -7
                           -7   = -7
OK. That's a true statement.
So x=0, y=1 is a solution.

Now check the other one I gave you:
x=2, y=3
                   9x - 7y = -7
                    9(2) - 7(3) = -7
                       18 - 21 = -7
                          -3    = -7
This is NOT a true statement.
So x=2, y=3 is NOT a solution to your equation.
I pulled a fast one on you. If I was charging you money for solutions,
then you would not pay me for this one, because it's not a solution.

8 0

3 years ago

forty-six out of the total 310 seniors graduate with honors. What is the ratio of seniors graduating with honors to the total nu

LekaFEV [45]

46 seniors graduate with honors out of 356 seniors

5 0

2 years ago

Which expression is equivalent to the expression shown?

Mumz [18]

Step-by-step explanation:

(A²)⁴ = A⁸

(D³)² = D⁶

(5⁴)² = 5⁸

5 0

2 years ago

Read 2 more answers

An advertising executive claims that there is a difference in the mean household income for credit cardholders of Visa Gold and

Maslowich

Answer:

Null hypothesis: $\mu_{Visa}=\mu_{Mastercard}$

Alternative hypothesis: $\mu_{Visa} \neq \mu_{Mastercard}$

$t=\frac{66970-59060}{\sqrt{\frac{9500^2}{11}+\frac{10000^2}{17}}}}=2.108$

$p_v =2*P(t_{26}>2.108)=0.0448$

Comparing the p value with the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and a would be a significant difference between the in the mean household income for credit cardholders of Visa Gold and of MasterCard Gold at 10% of significance .

Step-by-step explanation:

Data given and notation

$\bar X_{Visa}=66970$ represent the mean for Visa

$\bar X_{Mastercard}=59060$ represent the mean for the sample Mastercard

$s_{Visa}=9500$ represent the population standard deviation for Visa

$s_{Mastercard}=10000$ represent the population standard deviation for Mastercard

$n_{Visa}=11$ sample size for the group Visa

$n_{Mastercard}=17$ sample size for the group Mastercard

t would represent the statistic (variable of interest)

$\alpha=0.1$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis: $\mu_{Visa}=\mu_{Mastercard}$

Alternative hypothesis: $\mu_{Visa} \neq \mu_{Mastercard}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$z=\frac{\bar X_{Visa}-\bar X_{Masterdcard}}{\sqrt{\frac{s^2_{Visa}}{n_{Visa}}+\frac{s^2_{Mastercard}}{n_{Mastercard}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{66970-59060}{\sqrt{\frac{9500^2}{11}+\frac{10000^2}{17}}}}=2.108$

What is the p-value for this hypothesis test?

First we need to calculate the degrees of freedom given by:

$df= n_{Visa}+n_{Mastercard}-2 = 11+17-2= 26$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{26}>2.108)=0.0448$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.1$ we see that $p_v$ so we can conclude that we can reject the null hypothesis, and a would be a significant difference between the in the mean household income for credit cardholders of Visa Gold and of MasterCard Gold at 10% of significance .

4 0

2 years ago