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3 years ago

Can anyone tell me how to graph 7x+y=5

2 answers:

5 0

You have the equation 7x+y=5
But you must rearrange this into y=mx+b form
to do this subtract 7x from both sides

y= -7x+5

On the y axis plot a dot on 5 because that is the y intercept.

To find the x intercept let y=0
0= -7x+5
1. Subtract 5 to both sides
-5=-7x
2. Divide by -7 to both sides
x= -5/-7
x=5/7
The x intercept is 5/7, so on the x axis mark a dot on 5/7 which is approximately at 0.7
Once you have marked one dot on the y axis at 5 and another dot on the x-axis at 0.7 then you draw a straight line through these points and you have graphed the function 7x+y=5

MakcuM [25]3 years ago

4 0

To graph an equation, you first need to solve it for y. This means turning the equation into this form: Y=.......

For your equation, once you solve it for Y, you get this:

$y = -7x +5$

Now, the coefficient of X is a very crucial part of graphing an equation. Once the equation is solved for Y, the coefficient of X is going to be the slope of the line you are graphing. The slope of a line is how much Y goes up every time X is increased by 1.

To graph an equation, you need to put in a number for X and find the matching value for Y and then graph that point. To do this, you will need a coordinate plane. I can't show you what that looks like on here. But, I will do my best to explain how it is done.

Now, for your equation:

$y = -7x +5$

Simply chose a number for X and find the matching value for Y. I'll try 0 for an example:

$y = -7(0) +5$

-7 * 0 is 0. Therefore, your new equation looks like this:

$y =+5$

Therefore, one "Solution pair" to this equation is (X=0,Y=5)

Simply repeat this process and plot the solution pairs on the coordinate plane and then connect the dots.

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6 0

4 years ago

Anyone help??? Thank you need it in 3 min

den301095 [7]

Answer:

$40.352

Step-by-step explanation:

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3 years ago

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Eric cut a piece of wood into the shape of a trapezoid. The trapezoid has base lengths of 8 inches and 9 inches. The height of t

ivolga24 [154]

Answer:

110.5 inches

Step-by-step explanation:

A=(a+b)/2 h

A = (8+9)/2 * 13

A = 17/2 * 13

A = 110.5 inches

Hope this helped

4 0

2 years ago

Read 2 more answers

Find the quotien of 26,234 divide 42

icang [17]

Let's solve step by step

Step 1: First you need to know that quotient is the answer to a division problem.
Now that we know that we can just divide 26,234 by 42.

Step 1: Divide
You can Divide 26,234 by 42 using a calculator
once you typed in 26,234/42 than should equal 624.619047619

Step 3: Round (this step is optional)
To make the answer more clear we can round 624.619047619 to the hundreds place.

624.619047619 is rounded to 624.62

Therefore your answer is 624.619047619 or rounded to 624.62. (either answer will be correct)
Hope this helps! - Alyssa

(P.S It would mean a lot to me if you marked my answer as Brianliest answer, I am trying to get a higher ranking, Thanks) :)

3 0

4 years ago

To test Upper H 0: muequals50 versus Upper H 1: muless than50, a random sample of size nequals23 is obtained from a populatio

natta225 [31]

Answer:

Step-by-step explanation:

Hello!

To test H0: u= 50 versus H1= u < 50, a random sample size of n = 23 is obtained from a population that is known to be normally distributed. Complete parts A through D. 

 A) If ¯ x = 47.9 and s=11.9, compute the test statistic .

For thistest the corresponsing statistis is a one sample t-test

$t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }~~t_{n-1}$

$t_{H_0}= \frac{47.9-50}{\frac{11.9}{\sqrt{23} } } = -0.846= -0.85$

B) If the researcher decides to test this hypothesis at the a=0.1 level of significance, determine the critical value(s).

This test is one-tailed to the left, meaning that you'll reject the null hypothesis to small values of the statistic. The ejection region is defined by one critical value:

$t_{n-1;\alpha }= t_{22;0.1}= -1.321$

Check the second attachment. The first row shows α= Level of significance; the First column shows ν= sample size.

The t-table shows the values of the statistic for the right tail. P(tₙ≥α)

But keep in mind that this distribution is centered in zero, meaning that the right and left tails are numerically equal, only the sign changes. Since in this example the rejection region is one-tailed to the left, the critical value is negative.

C) What does the distribution graph appear like?

Attachment.

D) Will the researcher reject the null hypothesis?

As said, the rejection region is one-tailed to the right, so the decision rule is:

If $t_{H_0}$ ≤ -1.321, reject the null hypothesis.

If $t_{H_0}$ > -1.321, do not reject the null hypothesis.

$t_{H_0}$ = -0.85, the decision is to not reject the null hypothesis.

To test H0: μ=100 versus H1:≠100, a simple random sample size of nequals=24 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d).

a) If x =104.2 and s=9.6, compute the test statistic.

For this example you have to use a one sample t-test too. The formula of the statistic is the same:

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } = \frac{104.2-100}{\frac{9.6}{\sqrt{24} } = } = 2.143$

b) If the researcher decides to test this hypothesis at the α=0.01 level of significance, determine the critical values.

This hypothesis pair leads to a two-tailed rejection region, meaning, you'll reject the null hypothesis at either small or big values of the statistic. Then the rejection region is divided into two and determined by two critical values (the left one will be negative and the right one will be positive but the module of both values will be equal).

$t_{n-1;\alpha/2 }= t_{23; 0.005}= -2.807$

$t_{n-1;1-\alpha /2}= t_{23;0.995}= 2.807$

c) Draw a t-distribution that depicts the critical region(s). Which of the following graphs shows the critical region(s) in thet-distribution?

Attachment.

(d) Will the researcher reject the null hypothesis?

The decision rule for the two-tailed hypotheses pair is:

If $t_{H_0}$ ≤ -2.807 or if $t_{H_0}$ ≥ 2.807, reject the null hypothesis.

If -2.807 < $t_{H_0}$ < 2.807, do not reject the null hypothesis.

$t_{H_0}$ = 2.143 is greater than the right critical value, the decision is to reject the null hypothesis.

Correct option:

B. The researcher will reject the null hypothesis since the test statistic is not between the critical values.

Full text in attachment. The sample size is different by 2 but it should serve as a good example.

H₀: μ = 20

H₁: μ < 20

a) n= 18, X[bar]= 18.3, S= 4, Compute statistic.

$t_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }= \frac{18.3-20}{\frac{4}{\sqrt{18} } } = -1.80$

b) The rejection region in this example is one-tailed to the left, meaning that you'll reject the null hypothesis to small values of t.

Out of the three graphics, the correct one is A.

To resolve this you have to look for the values in the t-table that are the closest to the calculated $t_{H_0}$

Symbolically:

$t_{n-1;\alpha_1 } \leq t_{H_0}\leq t_{n-1;\alpha _2}$

$t_{H_0}$ = -1.80

$t_{17; 0.025 }= -2.110$

$t_{17;0.05}= -1.740$

Roughly defined you can say that the p-value is the probability of obtaining the value of $t_{H_0}$ , symbolically: P(t₁₇≤-1.80)

Under the distribution the calculated statistic is between the values of -2.110 and -1.740, then the p-value will be between their cumulated probabilities:

A. 0.025 < p-value < 0.05

d. The researcher decides to test the hypothesis using a significance level of α: 0.05

Using the p-value approach the decision rule is the following:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

We already established in item c) that the p-value is less than 0.05, so the decision is to reject the null hypothesis.

Correct option:

B. The researcher will reject the null hypothesis since the p-value is less than α.

I hope this helps!

6 0

3 years ago