All categories

2 years ago

Find the perimeter of the polygon.

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

6 0

Answer:

Step-by-step explanation:

The Two-Tangent Theorem states that if two tangent segments are drawn to one circle from the same external point, then they are congruent

13+13+9+9+12+12+6+6= 80

You might be interested in

22.5 + 7(n−3.4) simplified

NARA [144]

-1.3+7n is the answer

7 0

3 years ago

which graph represents the solution set of the system of inequalities? (is my selected answer correct, if not please help!!)

algol [13]

Answer:

the graph on the right-top

Step-by-step explanation:

Transferring an "x" to the right side in $x+y\ge-3$ , we get $y\ge -x-3$

The system of inequalities is

$\left \{ {{y$

We have y=2x+2 - ascending function with a=2, b=2

b=2 shows that ascending function intersects Y-axis is in y=2 - that situation is only on the right-top and left-down. So, we refuse left-top and right-down.

y=-x-3 - descending function with a=-1, b=-3

y<2x+2 is an area below the ascending function and we see that on the left-

$y\ge-x-3$ is an area above the descending function

On the left-down we have an area above both functions, so we refuse this picture

Right-top is correct

7 0

3 years ago

PLEASE HELP!! I’LL GIVE BRAINLIEST!!

lakkis [162]

Answer:

Step-by-step explanation:

[z^4/6²]^-3 = z^-12/6^-6 = 6^6/z^12

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

1) 12 3/10 + (-5 1/4)

puteri [66]

Answer:

1. 7.05

2. 18.075

3.4.0375

4.135/68

3 0

3 years ago

Find the perimeter of the polygon.​

Find the perimeter of the polygon.