How are the side lengths of a right triangle and the side lengths of a square related????/
2 answers:
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Answer:
option B
Step-by-step explanation:
Given :
Step 1 : simplify the equation :
Step 2: Arrange the terms :
Step 3 : Solve for x and y :
2x - 3y = - 9 ------ ( 1 )
5x - 2y = - 7 --------- ( 2 )
_____________________
( 1 ) x 5 => 10x - 15y = - 45 ---------- (3 )
( 2) x 2 => 10x - 4y = - 14 ----------- (4 )
_______________________
( 3 ) - ( 4 ) => 0x - 11y = - 31
- 11 y = - 31
Substitute y in ( 1 ) :
2x - 3y = - 9
Therefore the solution to the sytem is
The solution of the system of equation is a point which lies
on the both the lines.
Option A : False , It says the solution lies above one of the given line.
But the solution of the system of equation always lies on
both the line.
Option B : True , says the solution is a point on the coordinate plane.
Option C : False, because if the solution is on the x-axis , then
the y coordinate in the solution would be zero.
But it is not zero.
Option D : False , the solution is the point where both the lines intersect.
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 3x - 4y = 7 into this form
Subtract 3x from both sides
- 4y = - 3x + 7 ( divide all terms by - 4 )
y = x -
← in slope- intercept form
with slope =
• Parallel lines have equal slopes, hence
y = x + c ← is the partial equation of the parallel line
To find c substitute (- 4, - 2) into the partial equation
- 2 = - 3 + c ⇒ c = - 2 + 3 = 1
y = x + 1 ← in slope- intercept form
Multiply all terms by 4
4y = 3x + 4 ( subtract 4 from both sides )
4y - 4 = 3x ( subtract 4y from both sides )
- 4 = 3x - 4y, that is
3x - 4y = - 4 ← in standard form