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aev [14]
2 years ago
13

Write the slope intercept form of the equation of the line through the given point with the given slope

Mathematics
1 answer:
aleksandrvk [35]2 years ago
5 0

Given that,

Point = (-5,3)

Slope, m = -3/5

To find,

The slope intercept form of the equation of the line.

Solution,

The general form of equation is :

y = mx +b

We have, x = -5, y = 3

So,

3=\dfrac{-3}{5}(-5)+b\\\\3=-3+b\\\\b = 6

The equation is :

y=\dfrac{-3}{5}x+6

Hence, the required equation is y=\dfrac{-3}{5}x+6.

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Which of the following function types exhibit the end behavior (PICTURE INCLUDED)
Nostrana [21]

Answer:

y=x^n; n is even and greater than zero.

The absolute value function y=|x|

Step-by-step explanation:

The power function;

y=x^n; n is even and greater than zero, is symmetric with respect to the positive y-axis.

As x\rightarrow \infty,f(x)\rightarrow \infty and as x\rightarrow -\infty,f(x)\rightarrow \infty

The absolute value function y=|x| also has the same end behavior.

The remaining functions in the options provided do not exhibit this end behavior.

See graph in attachment.

4 0
3 years ago
What is the surface area of the rectangular prism?
Nadusha1986 [10]
348 in. 2

2·(8·9+6·9+6·8)=348
7 0
3 years ago
The admission fee at an amusement park is $4.00 for children and $5.60 for adults. On a certain day, 284 people entered the park
miv72 [106K]
4c+5.6d=1360
Let
Children (c)=x
Adults (d)=284-x

4x+5.6 (284-x)=1360
Solve for x
4x+1590.4-5.6x=1360
4x-5.6x=1360-1590.4
-1.6x=-230.4
X=230.4÷1.6
X=144 children

284−144=140 adults
3 0
3 years ago
Can an equilateral triangle ever be a right triangle too?
True [87]
No, it never can be a right triangle. 

First, all the angles of an equilateral triangle is 60 degrees because all angles are the same and all the angles add up to 180:

180/3 = 60.

So if it is a right angle it needs one angle 90 degrees which an equilateral triangle can't have,
7 0
3 years ago
Read 2 more answers
What is 5.300 equivalent to
S_A_V [24]
It is equivalent too 5.3 and 5.30
7 0
2 years ago
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