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Alina [70]
3 years ago
14

Aluminum has a density of 2.7 g/cm3, how much space in cm3 would 81 grams of aluminum occupy? Show steps to answering this equat

ion.
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

30 cm³

Explanation:

Step 1: Given data

  • Density of aluminum (ρ): 2.7 g/cm³
  • Mass of aluminum (m): 81 g
  • Volume occupied by aluminum (V): ?

Step 2: Calculate the volume occupied by aluminum

The density of aluminum is equal to its mass divided by its volume.

ρ = m/V

V = m/ρ

V = 81 g / 2.7 g/cm³

V = 30 cm³

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Andreas93 [3]
The particles move from an area of high concentration, to an area of low concentration, until the distribution of particles is equal
3 0
4 years ago
A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m
aliya0001 [1]

Answer:

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( q_{\ lost} )= heat absorbed by the less hotter  sample( q_{\ gain} )

The relationship between heat (q), mass (m) and temperature (t) is q = mc\Delta t

where c is specific heat capacity, \Delta t temperature change.

\Delta t = t_{\ final} - t_{\ initial}

equating both heat emitted and absorb

-q_{\ lost} = q_{\ gain}

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * (t_{final} - 330) = 30 *  (t_{final} - 280)

-50t_{final} + 16500 = 30t_{final} - 8400

80t_{final} = 16500+8400

80t_{final} = 24900

t_{final} = 24900/80 = 311.25k

8 0
3 years ago
Which statement related to particle and wave properties of matter is correct? a. Interference patterns are observed when a wave
DerKrebs [107]

Answer:

a. Interference patterns are observed when a wave passes through a barrier with two slits

Explanation:

Interference is a situation where two waves superimpose to form a new wave of a different amplitude. This amplitude can be greater, same or lower.

the diagram attached below shows the movement of a wave through a barrier with two slits.

you can notice the portions of the wave that overlap. This overlapping of waves is the interference.

Thus, option A is correct.

The other options however,  are not correct. as shown below:

Option B is wrong as waves exhibit diffraction <em>(it is diffraction of the light wave that produces the rainbows we see in the sky)</em>

Option C is wrong as waves do not travel straight through slits always.

Option D is wrong as waves can also interfere constructively and destructively.

7 0
4 years ago
Is Oxygen more reactive than Beryllium
Umnica [9.8K]
Yes, because beryllium is less dense and harder than oxygen.
5 0
3 years ago
Read 2 more answers
Why is carbon an element and not a compound?
Neko [114]

Answer:

Carbon is found in all living organisms.

8 0
3 years ago
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