Question

Find the diagonal of a square whose sides are of the given measure. Given =

Answer 1

Answer:

7$\sqrt{42}$

Step-by-step explanation:

The diagonal is the hypotenuse of the right triangle with legs 7$\sqrt{3}$

Use Pythagoras' identity to solve for the diagonal d

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

d² = (7$\sqrt{3}$)² + (7$\sqrt{3}$)²

    = 147 + 147

    = 294 ( take the square root of both sides )

d = $\sqrt{294}$ = 7$\sqrt{42}$ ≈ 45.37 ( to 2 dec. places )