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Evgesh-ka [11]
3 years ago
5

4Cr(s)+3O2 (g )= Cr2O3 (s) Find the theoretical yield in moles and grams

Chemistry
1 answer:
Assoli18 [71]3 years ago
7 0
The balanced reaction is:

<span>4Cr(s)+3O2 (g )= Cr2O3 (s)

Since we are not given the amount of any of the reactants, we assume we have one gram of chromium. Calculations are as follows:

1 g Cr ( 1 mol Cr / 52 g Cr ) ( 1 mol Cr2O3 / 4 mol Cr ) = <span>0.005 mol Cr2O3

</span></span>0.005 mol Cr2O3 (151.99 g Cr2O3 / 1 mol Cr2O3 ) = 0.7307 g <span>Cr2O3
</span>
Therefore, the theoretical yield for 1 gram of Cr is 0.005 mol Cr2O3 or 0.7307 g Cr2O3.
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520 kg

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Let's consider the combustion of isooctane.

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We can establish the following relations:

  • 1 mL of C₈H₁₈ has a mass of 0.690 g (ρ = 0.690 g/mL).
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50 L of isooctane require the following mass of air.

50 \times 10^{3}mLC_{8}H_{18}.\frac{0.690gC_{8}H_{18}}{1mLC_{8}H_{18}} .\frac{1molC_{8}H_{18}}{114.22gC_{8}H_{18}} .\frac{12.5molO_{2}}{1molC_{8}H_{18}} .\frac{1molAir}{0.21molO_{2}} .\frac{28.96 \times 10^{-3}kgAir}{1molAir} =520kgAir

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