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3 years ago

Helppp meee plzzz plzzzz Helppp

Chemistry

1 answer:

Rus_ich [418]3 years ago

7 0

Answer:F =MAX

Explanation:I did that

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So it can _____ ____ the egg’s exterior and enter

Dmitry_Shevchenko [17]

So it can break down the egg’s exterior and enter

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2 years ago

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A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?

neonofarm [45]

Answer:

$\boxed {\boxed {\sf 40.4299 \ Joules}}$

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

$PE= m \times g \times h$

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

m= 1.85 kg
g= 9.8 m/s²
h= 2.23 m

Substitute the values into the formula.

$PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m$

Multiply the first 2 numbers together.

$PE=18.13 \ kg*m/s^2 *2.23 \ m$

Multiply again.

$PE= 40.4299 \ kg*m^2/s^2$

1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

$PE= 40.4299 \ J$

The textbook has 40.4299 Joules of potential energy.

7 0

3 years ago

Draw a diagram to show what happens to the particles,when a liquid cools to a solid

Evgen [1.6K]

<h3>Hope it helps you.</h3>

do follow me if you appreciate it

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3 years ago

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the half-life of chromium 51 is 28 days if the sample contained 510 grams how much chromium would remain after 86 days

Anni [7]

Answer: 3.285714285714286 I believe this is what it is

Explanation:

You have to divide 50 by 28 then times it by 510 then divide by 86

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3 years ago

Calculate the number of oxygen atoms in a 50.0 sample of dinitrogen tetroxide . Be sure your answer has a unit symbol if necessa

GenaCL600 [577]

Answer:1.309 x 10^24 oxygen atoms

Explanation:

Molar mass of N2O4,= 2 x Molar mass of Nitrogen + 4 x Molar mass of Oxygen

= 2 x 14.01 + 4 x 16.0

= 92.02 g/mol

One mole of a substance is equal to 6.022 × 10²³ unit/ atoms/ molecules

In N2O4, there are 4 moles of Oxygen

if 92.02 g contains = 4 x 6.022 x 10 ^23 molecules

50.0 g wll contain= (4 x 6.022 x 10 ^23 x 50)/ 92.02g

1.309 x 10^24 oxygen atoms

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3 years ago