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natima [27]
4 years ago
13

What substance is oxidized in the reaction Mg + Cu2+ — Mg2+ + Cu?

Chemistry
1 answer:
alexgriva [62]4 years ago
8 0

Answer:

Mg

Explanation:

Mg + Cu2+ — Mg2+ + Cu

Magnesium is oxidized because its oxidation state increased from 0 to +2 while Cu is reduced because its oxidation state decreased from +2 to 0.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

<em>Consider the following reactions. </em>

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

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What is law of conservation of mass​
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Answer:

Mass in an isolated system can neither be destroyed nor created.

Explanation:

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3 years ago
Mass and volume can be used to describe what general property?
Wittaler [7]
3 dimensional figure
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How many formula units are 113.5 grams of Ca(OH)2
Sav [38]

Answer:

Molecular Formula Ca(OH)2 or CaH2O2

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Explanation:

8 0
3 years ago
What is the value of q when the solution contains 2.00×10−2 m sr2+ and 1.50×10−3m cro42−?
Law Incorporation [45]
Answer is: ion product for strontium chromate is 3·10⁻⁵.<span>
Balanced chemical reaction (dissociation) of strontium chromate:
</span>Sr²⁺(aq) + CrO₄²⁻(aq) → SrCrO₄.<span>
Qsp(</span>SrCrO₄) = c(Sr²⁺)·(CrO₄²⁻).<span>
c(</span>Sr²⁺) = 2.00·10⁻² M.
c(CrO₄²⁻) = 1.50·10⁻³ M.
Q = 2.00·10⁻² M · 1.50·10⁻³ M.
Q = 0.00003 = 3·10⁻⁵ M².
5 0
3 years ago
Read 2 more answers
Vermilion, a very rare and expensive solid natural pigment that has been used to print artists' signatures on works of art, is m
Anon25 [30]

To solve for moles use molar and volume:

M = mol/L

 

0.02700 m= mol/(.75 L)

 

mol = .036 mol of Hg(NO3)2

 

The proportion of Hg(NO3)2 to the Mercury that is used to create HgS is 1:1 so solve for the moles of Mercury used. So:

.036 * (1 Hg(NO3)2 / 1 Hg) = .036 moles of Hg used to make HgS

The proportion of Mercury to HgS is 1:1, as an alternative of doing the obvious math you can conclude that .036 moles of HgS will be produced because you're given .036 moles of Hg and an excess of S. Use the molar mass of HgS to determine how many grams will be produced.

 

.036 moles * 232.66 g/mol = 8.37576 grams of Vermilion is produced.

7 0
4 years ago
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