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3 years ago

What is law of sines

Mathematics

1 answer:

BaLLatris [955]3 years ago

8 0

Answer:

In trigonometry, the law of sines, sine law, sine formula, or sine rule is an equation relating the lengths of the sides of a triangle to the sines of its angles

The Law of Sines (or Sine Rule) is very useful for solving triangles:

a/sin A=b/sin B=c/sin C

hope this helps

have a good day :)

Step-by-step explanation:

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Jan is trying to increase her water intake to meet recommended guidelines. She currently consumes 2 (24 oz. each) bottles of wat

castortr0y [4]

Answer:

Extra 4 cups to make up 11 cups a day

Step-by-step explanation:

Here we have that Jan obtains 15% of her fluid needs from food, therefore, she gets the remaining 85 % from drinking water

If the recommended daily intake = 2.7 liters or 91.3 oz

And she already consumes 48 oz of water and 16 oz of milk

Note milk is equivalent to 0.87 water therefore total intake = 48 + 16*0.87= 61.92 oz

She needs to take additional (91.3 - 61.92) = 29.4 oz or 3.68 ≈ 4 cups extra to meet her recommended daily dosage.

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4 years ago

Calculate the average rate of change for the function

mezya [45]

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3 years ago

If there are 120 boys in the group, how many boys and girls are there TOTAL? Use the tape diagrams to solve.

Firdavs [7]

There are no girls???

6 0

3 years ago

Find the sum <br><br> 3/4 + 5/16

Dmitry_Shevchenko [17]

3/4 also equals 12/16 so 12/16+5/16= 17/16 or 1 1/16

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3 years ago

Read 2 more answers

Solve the triangle A = 2 B = 9 C =8

VARVARA [1.3K]

Answer:

$\begin{gathered} A=\text{ 12}\degree \\ B=\text{ 114}\degree \\ C=54\degree \end{gathered}$

Step-by-step explanation:

To calculate the angles of the given triangle, we can use the law of cosines:

$\begin{gathered} \cos (C)=\frac{a^2+b^2-c^2}{2ab} \\ \cos (A)=\frac{b^2+c^2-a^2}{2bc} \\ \cos (B)=\frac{c^2+a^2-b^2}{2ca} \end{gathered}$

Then, given the sides a=2, b=9, and c=8.

$\begin{gathered} \cos (A)=\frac{9^2+8^2-2^2}{2\cdot9\cdot8} \\ \cos (A)=\frac{141}{144} \\ A=\cos ^{-1}(\frac{141}{144}) \\ A=11.7 \\ \text{ Rounding to the nearest degree:} \\ A=12º \end{gathered}$

For B:

$\begin{gathered} \cos (B)=\frac{8^2+2^2-9^2}{2\cdot8\cdot2} \\ \cos (B)=\frac{13}{32} \\ B=\cos ^{-1}(\frac{13}{32}) \\ B=113.9\degree \\ \text{Rounding:} \\ B=114\degree \end{gathered}$ $\begin{gathered} \cos (C)=\frac{2^2+9^2-8^2}{2\cdot2\cdot9} \\ \cos (C)=\frac{21}{36} \\ C=\cos ^{-1}(\frac{21}{36}) \\ C=54.3 \\ \text{Rounding:} \\ C=\text{ 54}\degree \end{gathered}$

3 0

1 year ago