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expeople1 [14]
3 years ago
15

Find the area of rectangle whose length is -3/7 and breadth is 16/3​

Mathematics
1 answer:
Tems11 [23]3 years ago
5 0

Answer:

I'm gonna guess your length is positive and you made a typing mistake. If that's so....

Step-by-step explanation:

Area= length x breadth

       =\frac{3}{7\\} x \frac{16}{3}

       =\frac{16}{7}

       =2.29 unit^{2}

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Let's say

P = perimeter, L : Length and w : width

Then

P=2(L+w)=2L+2w=108

But 

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2L+2w=108\\2(6+2w)+2w=108\\12+4w+2w=108\\12+6w=108\\6w=108-12\\6w=96\\w=16

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We verify :

2L+2w=108\\2(38)+2(16)=108\\76+32=108\\108=108

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Width = w = 16

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