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4 years ago

Find the 20th term of the following sequence. -6, -4, -2, 0

Mathematics

1 answer:

posledela4 years ago

6 0

Answer:

32.

Step-by-step explanation:

This is an arithmetic sequence with first term a1 = -6 and common difference 2.

an = a1 + d(n - 1)

a20 = -6 + 2(20-1) = 32

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4(x+5)+4x+8

kvasek [131]

B.) 8(x+4) is the best choice

6 0

3 years ago

Read 2 more answers

Given that f(x) = x^2 - 4x +1, find the value of m if f(m) = -3

iragen [17]

a. Answer: m = 2

Step-by-step explanation:

f(x) = x² - 4x + 1

f(m) = m² - 4m + 1 = -3

m² - 4m + 4 = 0

(m - 2)(m - 2) = 0

m = 2

***************************************************

b. Answer: k = 2 and k = 5

Step-by-step explanation:

f(x) = x² - 7x + 14

f(k) = k² - 7k + 14 = 4

k² - 7k + 10 = 0

(k - 2)(k - 5) = 0

k = 2 k = 5

3 0

3 years ago

8% of what number is 2 :)

Alisiya [41]

8% of what number is 2 - 268832

8 0

3 years ago

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Aya = a1 + (n - 1)d

Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

Step-by-step explanation:

Given

a₁ = -33

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = -33 and d = 4 in the nth term of the sequence

$a_n=-33+\left(n-1\right)4$

$\:a_n=-33+4n-4$

$a_n=4n-37$

Thus, the nth term of the sequence is:

$a_n=4n-37$

now substituting n = 26 in the nth term to determine the 26th term of the sequence

$a_n=4n-37$

$a_{26}=4\left(26\right)-37$

$a_{26}=104-37$

$a_{26}=67$

Therefore, the 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

7 0

3 years ago

14n+6p-8n=18p for n is n=p/2 the answer to this question?

Hitman42 [59]

Answer:

Solved for n, n = 2p

Step-by-step explanation:

14n + 6p - 8n = 18p

6n + 6p = 18p

6n = 12p

n = 2p

3 0

3 years ago