Answer:
You need to include a picture or add more o the question because I can't solve it without the rest of the problem. All I know is 60 degrees and 18. But what is the 18?
Step-by-step explanation:
Answer:
Pr(X >42) = Pr( Z > -2.344)
= Pr( Z< 2.344) = 0.9905
Step-by-step explanation:
The scenario presented can be modeled by a binomial model;
The probability of success is, p = 0.65
There are n = 80 independent trials
Let X denote the number of drivers that wear a seat belt, then we are to find the probability that X is greater than 42;
Pr(X > 42)
In this case we can use the normal approximation to the binomial model;
mu = n*p = 80(0.65) = 52
sigma^2 = n*p*(1-p) = 18.2
Pr(X >42) = Pr( Z > -2.344)
= Pr( Z< 2.344) = 0.9905
<span>Here let the quadratic equation be ax^2 + bx + c
We know that a=5 from the question.
Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2).
However, let's assume that a2=1 and b2=6,
Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10
So, the equation is (5x-10)(x-6)</span>
Answer:
x=-2
Step-by-step explanation:
To solve this equation, we can use PEMDAS or Order of Operations.
Parenthesis
Exponents
Multiplication>Division
Addition>Subtraction
Using the various properties can also help make the equation easier.
First, solve for parenthesis using the distributive property.
Our equation is now : 3/4x+3=1/4x+2
Now, subtract 2 on both sides, to cancel out the positive 2 on the right.
3/4x+1=1/4x
Now subtract 3/4x from both sides.
1=-2/4x
Finally, to isolate x, divide both sides by -2/4
1/-2/4=-2
x=-2
Hope this helps!
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR
