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What is 8.05x10^-5 in standard notation

Marina CMI [18]

Answer: 0.0000805

Step-by-step explanation:

You move the decimal 5 places to the left of 8.05.

6 0

3 years ago

Element A combines with Element B at a ratio of 2:1 to make a particular substance. If you have 10 grams of element A in the sub

Marina86 [1]

If its a 2:1 ratio then 5.

5 0

2 years ago

The price of grapes, g, is $2.19 per pound. The price of bananas, b, is $0.59 per pound. The price of pears, p, is $1.49 per pou

AlekseyPX

Part A.
Before you can write any sort of expression, you need to define variables. "grapes g" is not a definition, so the exercise seems meaningless as written. It seems the intent is to ...
let g, b, p represent the numbers of pounds of grapes, bananas, and pears, respectively.

Then, the total cost of some weight of fruit is
2.19g + 0.59b + 1.49p

Part B.
For g=3, b=3, p=2, the expression evaluates to
2.19*3 +0.59*3 +1.49*2 = 11.32

The total cost of 3 pounds of grapes, 3 pounds of bananas, and 2 pounds of pears is ...
$11.32

3 0

2 years ago

Sandy is working with a carpenter to frame a house. They are using 8-foot-long boards, but each board must be cut to be 7 feet i

Tju [1.3M]

Answer:

5/4in

Step-by-step explanation:

The initial length:

1 ft = 12 in

8 ft = 8 * 12 in

= 96 in

The final length:

7 ft 10 3/4 in = 7 ft + 10 in + 3/4 in

= 7 * 12 in + 10 in + 3/4 in

= 84 in + 10 in + 3/4 in

= 94 in + 3/4 in

The final length:

96 in - 94 in - 3/4 in = 2 in - 3/4 in = 8/4 in - 3/4 in = 5/4 in

8 0

3 years ago

In Illinois, 9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders; that is, they have been arre

Veseljchak [2.6K]

Answer:

a) 21.58% probability that exactly 3 people are repeat offenders

b) 97.91% probability that at least one person is a repeat offender

c) 3.69

d) 1.83

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

9% of all drivers arrested for DUI (Driving Under the Influence) are repeat offenders

This means that $p = 0.09$

41 people arrested for DUI in Illinois are selected at random.

This means that $n = 41$

a. What is the probability that exactly 3 people are repeat offenders?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{41,3}.(0.09)^{3}.(0.91)^{38} = 0.2158$

21.58% probability that exactly 3 people are repeat offenders

b. What is the probability that at least one person is a repeat offender?

Either none are repeat offenders, or at least one is. The sum of the probabilities of these outcomes is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ .

Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = 0) = C_{41,0}.(0.09)^{0}.(0.91)^{41} = 0.0209$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0209 = 0.9791$

97.91% probability that at least one person is a repeat offender

c. What is the mean number of repeat offenders?

$E(X) = np = 41*0.09 = 3.69$

d. What is the standard deviation of the number of repeat offenders?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{41*0.09*0.91} = 1.83$

4 0

2 years ago