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3 years ago

Can someone helps mezzzz

Mathematics

1 answer:

zmey [24]3 years ago

7 0

Answer: x=55

180-125=55

Explanation: Supplementary angles are equal to 180°, and vertical angles are congruent.

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Simplify completely****

andreyandreev [35.5K]

Answer:

$\displaystyle \frac{x + 7}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients
Factoring

Step-by-step explanation:

Step 1: Define

$\displaystyle \frac{x^2 + 12x + 35}{3x + 15}$

Step 2: Simplify

[Fraction] Factor numerator: $\displaystyle \frac{(x + 5)(x + 7)}{3x + 15}$
[Fraction] Factor denominator: $\displaystyle \frac{(x + 5)(x + 7)}{3(x + 5)}$
[Fraction] Divide: $\displaystyle \frac{x + 7}{3}$

4 0

3 years ago

Writte three numbers greater than 20 that has a 9 as a factor

mestny [16]

27, 36, 45

Hope it helps ^^

7 0

3 years ago

Plz help me!!!

Nadya [2.5K]

To solve this we are going to use the exponential function: $f(t)=a(1(+/-)b)^t$
where
$f(t)$ is the final amount after $t$ years
$a$ is the initial amount
$b$ is the decay or grow rate rate in decimal form
$t$ is the time in years

Expression A
$f(t)=624(0.95)^{4t}$
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate $b$ , we are going to use the formula: $b=|1-base|$ *100%
$b=|1-0.95|$ *100%
$b=0.05$ *100%
$b=$ 5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at $t=0$
$f(t)=624(0.95)^{4t}$
$f(0)=624(0.95)^{0t}$
$f(0)=624(0.95)^{0}$
$f(0)=624(1)$
$f(0)=624$
We can conclude that the initial value of expression A is 624.

Expression B
$f(t)=725(1.12)^{3t}$
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
$b=|1-base|$ *100%
$b=|1-1.12|$ *100
$b=|-0.12|$ *100%
$b=0.12$ *100%
$b=$ 12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at $t=0$
$f(t)=725(1.12)^{3t}$
$f(0)=725(1.12)^{0t}$
$f(0)=725(1.12)^{0}$
$f(0)=725(1)$
$f(0)=725$
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0

3 years ago

Write the equation of the line whose slope is m=−9 and y-intercept is (0,5) in Slope Intercept Form. Show all work below.

alexgriva [62]

Y=mx+b is slope intercept form...
m=slope
b=y-intercept
Answer- y=-9+5

5 0

3 years ago

Read 2 more answers

What are the solutions of this quadratic equation? x + 2x=-2

natta225 [31]

Answer:

2x=2