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MissTica
3 years ago
10

Yall are doing great thanks sm for the help

Mathematics
1 answer:
blondinia [14]3 years ago
4 0

Answer:

That is an obtuse isosceles

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You have $4.10 in nickels, dimes, and quarters. If you have twice as many dimes as quarters, and five more nickels than dimes, h
lutik1710 [3]

For this case, the first thing to do is define variables.

We have then:

  • <em>x: number of nickels </em>
  • <em>y: number of dimes </em>
  • <em>z: number of quarters </em>

We write now the system of equations:

0.05x + 0.1y + 0.25z = 4.10\\y = 2z\\x = y + 5

Then rewriting the equations we have:

0.05 (2z + 5) + 0.1 (2z) + 0.25z = 4.1\\0.05 (2z + 5) + 0.1 (2z) + 0.25z = 4.1\\0.1z + 0.25 + 0.2z + 0.25z = 4.1\\0.55z = 4.1-0.25

z = \frac {3.85} {0.55}\\z = 7

Then, substituting values we have:

y = 2 (7)\\y = 14

Finally:

x = 14 + 5\\x = 19

Answer:

19 nickels

14 dimes

7 quarters

6 0
4 years ago
Help it’s in the picture
blondinia [14]
The answer is 5 because the reasons are that it completes the question that is asked
5 0
4 years ago
Simplify<br> 5 x 5²<br> leaving your answer in index form.
kotegsom [21]

Answer:125

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use the information given to enter an equation in standard form.
Greeley [361]

Answer:

y = -2x + 25

Step-by-step explanation:

A standard equation can be in slope-intercept form: y = mx + b

m is the slope, b is the y-intercept.

Plug in the given slope.

y = -2x + b

To find b, plug in the given point (9, 7).

7 = -2(9) + b

Multiply.

7 = -18 + b

Add 18 to both sides to find b.

25 = b

Plug this into your standard equation.

y = -2x + 25

Check by plugging in the given point again.

7 = -2(9) + 25

7 = -18 + 25

7 = 7

Your answer is correct!

Hope this helps!

3 0
3 years ago
Employees from A and company B receive annual bonuses. What information would you need to test the claim that the difference in
lyudmila [28]

Answer:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

Step-by-step explanation:

1. The required information are

The average annual bonuses, \bar {x}_1 received by employees from company A

The average annual bonuses, \bar {x}_2 received by employees from company B

The standard deviation, σ₁, of the average annual bonuses for employees from company A

The standard deviation, σ₂, of the average annual bonuses for employees from company A

The number of employees in company A, n₁

The number of employees in company B, n₂

2. The null hypothesis is H₀: \bar {x}_1 - \bar {x}_2 ≤ 100

The alternative hypothesis is Hₐ: \bar {x}_1 - \bar {x}_2 > 100

The z value for the hypothesis testing of the difference between two means is given as follows;

z=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

At 0.5 level of significance, the critical z_\alpha = ± 0

The rejection region is z > z_\alpha and z < -z_\alpha

Therefore, the value of z obtained from the relation above more than or less than 0, we reject the null hypothesis, and we fail to reject the alternative hypothesis.

7 0
3 years ago
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