The two numbers are 15 and 6
<em><u>Solution:</u></em>
Let the two number be "a" and "b"
Let the first number be "a" and second number be "b"
Given that,
<em><u>The difference between two numbers is 9</u></em>
a - b = 9 -------- eqn 1
<em><u>The first number plus twice the other number is 27</u></em>
First number + twice the second number = 27
a + 2b = 27 ---------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
a = 9 + b ------ eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
9 + b + 2b = 27
3b = 27 - 9
3b = 18
Divide both sides of equation by 3
<h3>b = 6</h3>
<em><u>Substitute b = 6 in eqn 3</u></em>
a = 9 + 6
<h3>a = 15</h3>
Thus the two numbers are 15 and 6
