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muminat
3 years ago
12

There are 135 people in a sport centre. 73 people use the gym. 59 people use the swimming pool. 31 people use the track. 19 peop

le use the gym and the pool. 9 people use the pool and the track. 16 people use the gym and the track. 4 people use all three facilities. A person is selected at random. What is the probability that this person doesn't use any facility?
Mathematics
2 answers:
mylen [45]3 years ago
8 0

Answer:

Probability that this person doesn't use any facility is 0.09.

Step-by-step explanation:

We are given that there are 135 people in a sport center. 73 people use the gym. 59 people use the swimming pool. 31 people use the track. 19 people use the gym and the pool. 9 people use the pool and the track. 16 people use the gym and the track. 4 people use all three facilities.

Let Probability that people use the gym = P(G) = \frac{73}{135} = 0.54

Probability that people use the swimming pool = P(S) = \frac{59}{135} = 0.44

Probability that people use the track = P(T) = \frac{31}{135} = 0.23

Probability that people use the gym and the pool = P(G \bigcap S) = \frac{19}{135} = 0.14

Probability that people use pool and the track = P(S \bigcap T) = \frac{9}{135} = 0.07

Probability that people use the gym and the track = P(G \bigcap T) = \frac{16}{135} = 0.12

Probability that people use all three facilities = P(G \bigcap S \bigcap T) = \frac{4}{135} = 0.03

Now, first we will find the probability of person using at least one of the facility, i.e.; P(G \bigcup S \bigcup T)

As, P(G \bigcup S \bigcup T) = P(G) + P(S) + P(T) - P(G \bigcap S) - P(G \bigcap S) - P(G \bigcap S) + P(G \bigcap S \bigcap T)

So, P(G \bigcup S \bigcup T) = 0.54 + 0.44+0.23-0.14-0.07-0.12+0.03

                            = 1.24 - 0.33 = 0.91

Therefore, Probability that this person is using at least one of the facility is 0.91.

So, Probability that this person doesn't use any facility = 1 - Probability that this person is using at least one of the facility is 0.91

= 1 - 0.91 = 0.09

Hence, probability that this person doesn't use any facility is 0.09.

wlad13 [49]3 years ago
7 0

Answer:

Probability that the person doesn't use any facility = 0.0889

Step-by-step explanation:

Total number of people in a sports center = 135

Number of people using gym 'G' = 73

Number of people using swimming pool 'P' = 59

Number of people using track 'T' = 31

Number of people using gym and pool (G∩P) = 19

Number of people using pool and track (P∩T) = 9

Number of people using gym and track (G∩T) = 16

Number of people using all three facilities (G∩P∩T) = 4

Therefore, from the rule of compound probability,

P(GUPUT) = P(G) + P(P) + P(T) - P(G∩P) - P(G∩T) - P(P∩T) + p(G∩P∩T)

We know probability of an event = \frac{\text{Favorable event}}{\text{Total outcomes}}

We will plug in the values of probabilities of each event in the formula.

P(GUPUT) = \frac{73}{135}+\frac{59}{135}+\frac{31}{135}-\frac{19}{135}-\frac{9}{135}-\frac{16}{135}+\frac{4}{135}

                 = \frac{1}{135}(73+59+31-19-9-16+4)

                 = \frac{123}{135}

And probability that a person doesn't use any facility = 1 - P(GUPUT)

= 1 - \frac{123}{135}

= \frac{135-123}{135}

= \frac{12}{135}

= \frac{4}{45} ≈ 0.0889

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