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Kitty [74]
4 years ago
5

Based on the recipe for the Dextrose Calcium Carbonate (DCC) medium, what is the percent concentration (%weight/volume) of dextr

ose? Note: the recipe is based on a final volume of 1 L, not 100 ml. Here is the recipe:5.0g Yeast Extract, 1.0g K2HPO4, 0.5g MgSO4, 20.0g Dextrose (Glucose), 10.g CaCO3, 18.0g Agar, and 1.0 L dH2O
Chemistry
1 answer:
yanalaym [24]4 years ago
4 0

<u>Answer:</u> The percent concentration ( % m/v) of dextrose in the solution is 2 %

<u>Explanation:</u>

We are given:

Mass of Yeast Extract = 5.0 grams

Mass of K_2HPO_4 = 1.0 grams

Mass of MgSO_4 = 0.5 grams

Mass of Dextrose = 20.0 grams

Mass of CaCO_3 = 10. grams

Mass of Agar = 18.0 grams

Volume of solution = 1 L = 1000 mL      (Conversion factor: 1 L = 1000 mL)

% (m/v) is defined as the concentration, which is mass of solute present in 100 mL of solution

To calculate the mass of solute, we apply unitary method:

In 1000 mL of solution, the mass of dextrose present is 20.0 grams

So, in 100 mL of solution, the mass of dextrose present will be = \frac{20.0}{1000}\times 100=2g

Calculating the % (m/v) of dextrose, we get:

\% \text{(m/v) of dextrose}=\frac{\text{Mass of dextrose}}{\text{Volume of solution}}\times 100\\\\\% \text{(m/v) of dextrose}=\frac{2g}{100mL}\times 100=2\%

Hence, the percent concentration ( % m/v) of dextrose in the solution is 2 %

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