Sodium Oxide (Na2O) can react with hydrochloric acid (HCl) to produce sodium chloride (NaCl) and water (H2O) according to the fo

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2 years ago

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Sodium Oxide (Na2O) can react with hydrochloric acid (HCl) to produce sodium chloride (NaCl) and water (H2O) according to the fo

llowing equation: Na2O + 2HCl -> 2NaCl + H2O How many total atoms are present before and after the reaction? A) 2 before and 2 after
B) 3 before and 3 after
C) 5 before and 5 after
D) 7 before and 7 after

Chemistry

2 answers:

nika2105 [10] · Answer 1 · 2022-06-14T13:23:16+03:00

nika2105 [10]2 years ago

6 0

The answer is D) 7 before and 7 after

Just had this question

Sonbull [250] · Answer 2 · 2022-06-14T12:22:30+03:00

Answer:

D) 7 before and 7 after

Step-by-step explanation:

Na₂O + 2HCl ⟶ 2NaCl + H₂O

3 atoms + 4 atoms ⟶ 2×2 atoms + 3 atoms

7 atoms ⟶ 4 atoms + 3 atoms

7 atoms ⟶ 7 atoms

There are seven atoms present before and after the reaction.