Question

An evil supervillian has launched a drone from his/her submarine. The drone's height, in meters above sea level, as a function of time, t , in seconds, is given by h ( t ) = − 4.9t^2 + 133t + 152
What is the maximum height? Round your answer to three decimal places.

Answer 1

Answer:

the maximum height is 1054.500 meters

Step-by-step explanation:

h ( t ) = − 4.9t^2 + 133t + 152

a= -4.9 , b= 133  and c= 152

To find maximum height , we find vertex

$x= \frac{-b}{2a}=\frac{-133}{2(-4.9)}= 13.5714$

Now plug in 13.5714 for 't' in h(t)

$h(t) =-4.9t^2 + 133t + 152$

$h(t)=-4.9( 13.5714)^2 + 133( 13.5714)+ 152=1054.500$

the maximum height = 1054.500 meters