Plug in for x.
7(2y - 4) + 5y = -66
14y - 28 + 5y = -66
19y - 28 = -66
19y = -38
y = -2
Put it back into the equation.
2(-2) - 4 = -8
x = -8
The x-value is x = -8
Answer:
The area of the square adjacent to the third side of the triangle is 11 units²
Step-by-step explanation:
We are given the area of two squares, one being 33 units² the other 44 units². A square is present with all sides being equal, and hence the length of the square present with an area of 33 units² say, should be x² = 33 - if x = the length of one side. Let's make it so that this side belongs to the side of the triangle, to our convenience,
x² = 33,
x =
.... this is the length of the square, but also a leg of the triangle. Let's calculate the length of the square present with an area of 44 units². This would also be the hypotenuse of the triangle.
x² = 44,
x =
.... applying pythagorean theorem we should receive the length of a side of the unknown square area. By taking this length to the power of two, we can calculate the square's area, and hence get our solution.
Let x = the length of the side of the unknown square's area -
=
+
,
x =
... And
squared is 11, making the area of this square 11 units².
my issues is how we finna see this it's small but I think that it could be 25 or 7
Answer:
x-intercept = 4
y-intercept = -1
As ordered pairs they would be ( 4, 0) and ( 0, -1)
Step-by-step explanation:
The line goes through 4 on the x line and goes through -1 on the y line.
As an ordered pair you just put the numbers in their x and y spots being ( x, y )
With 4 being on the X and -1 being on the Y it would make them ( 4, 0) and
( 0, -1).
Answer:
2
a) 6.37%
b) 6.25%
3
a) 0.60 %
b) 0.59 %
Step-by-step explanation:
2 )
a) With replacement
Probability of extracting a club is 13/52
Probability of extracting a spade is 13/51
13/52 * 13/51
= 6.37 %
b) Without replacement
13/52 * 13/52
= 6.25 %
3) With replacement
Probability of extracting a ace is 4/52
Probability of extracting a queen is 4/51
4/52 * 4/51
= 0.60 %
b) Without replacement
4/52 * 4/52
= 0.59 %