State the angle from 1:00 to 2:30
2 answers:
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Check the picture below.
let's recall that once we move an angle in the opposite direction of the 0-line or x-axis, we end up with a negative counterpart angle.
since we know that θ is on the IV Quadrant, then its negative counterpart must be across the line, and tangent is negative on the IV Quadrant, and positive on the I Quadrant.
Answer:
Step-by-step explanation:
There is an error in the question. The table does not show two linear functions. y₁ is a linear function, but y₂ is not a straight line. It makes a bend at (-6,1).
Line 1 goes through (-12,-3) and (0,5).
slope = (5-(-3))/(0-(-12)) = 2/3
y-intercept = 5
y₁ = (2/3)x + 5
Line 2 goes through (-12,-2) and (-6,1).
slope = (1-(-2))/(-6-(-12)) = 1/2
y₂ = (1/2)x + 4
(2/3)x + 5 = (1/2)x + 4
x = -6
y = (2/3)x + 5 = 1
Solution: (-6,1)
